下面的练习题出自LeetCode:https://leetcode-cn.com/problemset/database/,有兴趣的能够去上面刷刷题sql
练习题1:超过经理收入的员工spa
分析:code
使用sql自链接查询,由于员工Id和经理的ManagerId都在同一个表,使用自链接,能够把一张表看做2张表来使用,一张为员工表ygb,一张为经理表jlb;blog
查询思路就是:筛选出员工表的ManagerId与经理表的Id相等的记录,而后在这些记录中筛选员工表的Salary大于经理表的Salary的记录leetcode
SELECT * FROM employee ygb,employee jlb WHERE ygb.ManagerId = jlb.Id
SELECT * FROM employee ygb,employee jlb WHERE ygb.ManagerId = jlb.Id AND ygb.Salary>jlb.Salary
SELECT ygb.name AS Employee FROM employee ygb,employee jlb WHERE ygb.ManagerId = jlb.Id AND ygb.Salary>jlb.Salary
练习题2:删除重复的电子邮箱get
分析:
先使用自链接查询,用自身表和本身比较,来判断哪些重复邮箱class
SELECT * FROM Person p1, Person p2
这样获得一个2个相同表的笛卡尔积,即两张表的组合结果im
能够分别查询p1.*和p2.*d3
接着查重数据
SELECT p1.* FROM Person p1, Person p2 WHERE p1.Email = p2.Email AND p1.Id>p2.Id
而后删除重复数据便可
DELETE p1.* FROM Person p1, Person p2 WHERE p1.Email = p2.Email AND p1.Id>p2.Id
2019-09-04 22:47:00