oracle 用 正则表达式拆分字符串（逗号）

                        SELECT DISTINCT REGEXP_SUBSTR (c.RFID,'[^,]+',1,LEVEL) as RFID FROM  CAR_BASIC c WHERE c.RFID IS NOT NULL AND c.RFID != 'E2003031180C027020903C6E' CONNECT BY REGEXP_SUBSTR (c.R

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