Java设计模-过滤器模式

过滤器模式
过滤器模式(Filter Pattern)或标准模式(Criteria Pattern)是一种设计模式,这种模式允许开发人员使用不同的标准来过滤一组对象,通过逻辑运算以解耦的方式把它们连接起来。这种类型的设计模式属于结构型模式,它结合多个标准来获得单一标准。
实现
我们将创建一个  Person 对象、 Criteria 接口和实现了该接口的实体类,来过滤  Person 对象的列表。 CriteriaPatternDemo,我们的演示类使用  Criteria 对象,基于各种标准和它们的结合来过滤  Person 对象的列表。
步骤 1
创建一个类,在该类上应用标准。
Person.java
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public class Person {
 
      private String name;
      private String gender;
      private String maritalStatus;
 
      public Person(String name,String gender,String maritalStatus){
         this.name = name;
         this.gender = gender;
         this.maritalStatus = maritalStatus;       
      }
 
      public String getName() {
         return name;
      }
      public String getGender() {
         return gender;
      }
      public String getMaritalStatus() {
         return maritalStatus;
      
   }
步骤 2
为标准(Criteria)创建一个接口。
 
Criteria.java
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import java.util.List;
 
    public interface Criteria {
       public List<Person> meetCriteria(List<Person> persons);
    }
步骤 3
创建实现了  Criteria 接口的实体类。
 
CriteriaMale.java
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import java.util.ArrayList;
    import java.util.List;
 
    public class CriteriaMale implements Criteria {
 
       @Override
       public List<Person> meetCriteria(List<Person> persons) {
          List<Person> malePersons = new ArrayList<Person>();
          for (Person person : persons) {
             if(person.getGender().equalsIgnoreCase("MALE")){
                malePersons.add(person);
             }
          }
          return malePersons;
       }
    }
CriteriaFemale.java
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import java.util.ArrayList;
    import java.util.List;
 
    public class CriteriaFemale implements Criteria {
 
       @Override
       public List<Person> meetCriteria(List<Person> persons) {
          List<Person> femalePersons = new ArrayList<Person>();
          for (Person person : persons) {
             if(person.getGender().equalsIgnoreCase("FEMALE")){
                femalePersons.add(person);
             }
          }
          return femalePersons;
       }
    }
CriteriaSingle.java
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import java.util.ArrayList;
    import java.util.List;
 
    public class CriteriaSingle implements Criteria {
 
       @Override
       public List<Person> meetCriteria(List<Person> persons) {
          List<Person> singlePersons = new ArrayList<Person>();
          for (Person person : persons) {
             if(person.getMaritalStatus().equalsIgnoreCase("SINGLE")){
                singlePersons.add(person);
             }
          }
          return singlePersons;
       }
    }
AndCriteria.java
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import java.util.List;
 
    public class AndCriteria implements Criteria {
 
       private Criteria criteria;
       private Criteria otherCriteria;
 
       public AndCriteria(Criteria criteria, Criteria otherCriteria) {
          this.criteria = criteria;
          this.otherCriteria = otherCriteria;
       }
 
       @Override
       public List<Person> meetCriteria(List<Person> persons) {
          List<Person> firstCriteriaPersons = criteria.meetCriteria(persons);     
          return otherCriteria.meetCriteria(firstCriteriaPersons);
       }
    }
OrCriteria.java
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import java.util.List;
 
    public class OrCriteria implements Criteria {
 
       private Criteria criteria;
       private Criteria otherCriteria;
 
       public OrCriteria(Criteria criteria, Criteria otherCriteria) {
          this.criteria = criteria;
          this.otherCriteria = otherCriteria;
       }
 
       @Override
       public List<Person> meetCriteria(List<Person> persons) {
          List<Person> firstCriteriaItems = criteria.meetCriteria(persons);
          List<Person> otherCriteriaItems = otherCriteria.meetCriteria(persons);
 
          for (Person person : otherCriteriaItems) {
             if(!firstCriteriaItems.contains(person)){
             firstCriteriaItems.add(person);
             }
          }   
          return firstCriteriaItems;
       }
    }
步骤4
使用不同的标准(Criteria)和它们的结合来过滤  Person 对象的列表。
 
CriteriaPatternDemo.java
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public class CriteriaPatternDemo {
       public static void main(String[] args) {
          List<Person> persons = new ArrayList<Person>();
 
          persons.add(new Person("Robert","Male", "Single"));
          persons.add(new Person("John","Male", "Married"));
          persons.add(new Person("Laura","Female", "Married"));
          persons.add(new Person("Diana","Female", "Single"));
          persons.add(new Person("Mike","Male", "Single"));
          persons.add(new Person("Bobby","Male", "Single"));
 
          Criteria male = new CriteriaMale();
          Criteria female = new CriteriaFemale();
          Criteria single = new CriteriaSingle();
          Criteria singleMale = new AndCriteria(single, male);
          Criteria singleOrFemale = new OrCriteria(single, female);
 
          System.out.println("Males: ");
          printPersons(male.meetCriteria(persons));
 
          System.out.println("\nFemales: ");
          printPersons(female.meetCriteria(persons));
 
          System.out.println("\nSingle Males: ");
          printPersons(singleMale.meetCriteria(persons));
 
          System.out.println("\nSingle Or Females: ");
          printPersons(singleOrFemale.meetCriteria(persons));
       }
 
       public static void printPersons(List<Person> persons){
          for (Person person : persons) {
             System.out.println("Person : [ Name : " + person.getName()
                +", Gender : " + person.getGender()
                +", Marital Status : " + person.getMaritalStatus()
                +" ]");
          }
       }     
    }
步骤 5
验证输出。
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Males:
     Person : [ Name : Robert, Gender : Male, Marital Status : Single ]
     Person : [ Name : John, Gender : Male, Marital Status : Married ]
     Person : [ Name : Mike, Gender : Male, Marital Status : Single ]
     Person : [ Name : Bobby, Gender : Male, Marital Status : Single ]
 
     Females:
     Person : [ Name : Laura, Gender : Female, Marital Status : Married ]
     Person : [ Name : Diana, Gender : Female, Marital Status : Single ]
 
     Single Males:
     Person : [ Name : Robert, Gender : Male, Marital Status : Single ]
     Person : [ Name : Mike, Gender : Male, Marital Status : Single ]
     Person : [ Name : Bobby, Gender : Male, Marital Status : Single ]
 
     Single Or Females:
     Person : [ Name : Robert, Gender : Male, Marital Status : Single ]
     Person : [ Name : Diana, Gender : Female, Marital Status : Single ]
     Person : [ Name : Mike, Gender : Male, Marital Status : Single ]
     Person : [ Name : Bobby, Gender : Male, Marital Status : Single ]
     Person : [ Name : Laura, Gender : Female, Marital Status : Married ]