ID连续的状况下(注意不能带where,不然结果很差):sql
SELECT * FROM `mm_account` AS t1 JOIN (SELECT ROUND(RAND() * (SELECT MAX(id) FROM `mm_account`)) AS id) AS t2 WHERE t1.id >= t2.id ORDER BY t1.id ASC LIMIT 4;
ID不连续的状况下:spa
SELECT * FROM `mm_account` WHERE id >= (SELECT floor(RAND() * (SELECT MAX(id) FROM `mm_account`))) and city="city_91" and showSex=1 ORDER BY id LIMIT 4;
假设你的表叫作mm_account,而且有一个字段叫id。最快的方法以下(随机获取5条):code
SELECT * FROM mm_account WHERE id >= ((SELECT MAX(id) FROM mm_account)-(SELECT MIN(id) FROM mm_account)) * RAND() + (SELECT MIN(id) FROM mm_account) limit 5;
若是带where语句,上面就不适合了。带where语句请看下面:ci
SELECT * FROM `mm_account` AS t1 JOIN (SELECT ROUND(RAND() * ( (SELECT MAX(id) FROM `mm_account` where id<1000 )-(SELECT MIN(id) FROM `mm_account` where id<1000 ))+(SELECT MIN(id) FROM `mm_account` where id<1000 )) AS id) AS t2 WHERE t1.id >= t2.id ORDER BY t1.id LIMIT 5;