语句:
if 条件表达式:
code1
code2
当条件表达式成立时,返回True,执行对应的代码块python
job = "programmer" if job == "programmer": print("钱多") print("话少") print("*的早")
语句:
if 条件表达式:
code1 ..
else:
code2 ...code
job = "programmer" if job == "programmer": print("钱多") print("话少") print("*的早") else: print("给你小红花儿~")
语句:
if 条件表达式1:
code1
elif 条件表达式2:
code2
elif 条件表达式3:
code3
else:
code4对象
money = False car = False house = False if money == True: print("你是土豪么???") elif car == True: print("你是有一辆蹦蹦嘛???") elif house == True: print("你是什么房子啊?") else: print("你是个好人~")
单项分支,双向分支,多项分支的互相嵌套组合it
money = False car = True house = True if money == True: print("你是土豪么???") if house == True: print("你是什么房子啊?") if car == True: print("你是有一辆蹦蹦嘛???") else: print("其实还能够~") else: print("感受差点意思~") else: print("你是个好人~")
# 打印1~100全部数字 i = 1 while i <= 100: print(i) i += 1
# 打印1~100的累加和 i = 0 total = 0 while i <= 100: total += i i += 1 print(total)
while True: print("死循环")
while True: pass
# 1~10,遇到5终止循环 i = 1 while i <= 10: print(i) if i == 5: break i += 1
# 打印1~100中不含4的数字 i = 1 while i <= 100: strvar = str(i) if "4" in strvar: i += 1 continue print(i) i += 1
循环/遍历/迭代,把容器中的元素一个个取出来for循环
# Error # setvar = {"a", "b", "c"} # i = 0 # while i < len(setvar): # print(setvar[i]) # i+=1
for 变量 in Iterable:
code1class
Iterable可迭代性数据效率
range(开始值,结束值,步长)
区间为[开始值,结束值),为左闭右开区间,右边的结束值取不到容器