Linux shell脚本007（select菜单选项）

#!/bin/bash names=( "张三" "李四" "王二" ) echo "Please guess who is my friend :" select var in ${names[@]} do if [ x$var = x"李四" ]; then #这里$var和"李四"前边的x，，是为了不，当输入的选择不在s

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