Say you have an array for which the ith element is the price of a given stock on day i.html
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.数组
这道题至关简单,感受达不到Medium的难度,只须要遍历一次数组,用一个变量记录遍历过数中的最小值,而后每次计算当前值和这个最小值之间的差值最为利润,而后每次选较大的利润来更新。当遍历完成后当前利润即为所求,代码以下:post
C++ 解法:url
class Solution { public: int maxProfit(vector<int>& prices) { int res = 0, buy = INT_MAX; for (int price : prices) { buy = min(buy, price); res = max(res, price - buy); } return res; } };
Java 解法:spa
public class Solution { public int maxProfit(int[] prices) { int res = 0, buy = Integer.MAX_VALUE; for (int price : prices) { buy = Math.min(buy, price); res = Math.max(res, price - buy); } return res; } }
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