Spring security笔记1/4: 第一个 SpringSecurity 应用

第一个 SpringSecurity 应用

Spring Security 官方介绍 https://spring.io/projects/spring-security#learn

Spring Security 目标是解决 “你是谁？”、“你能作什么？”两个问题。

实现步骤

1. 建立目录结构

|____spring-security-learn-1
| |____build.gradle
| |____src
| | |____main
| | | |____java
| | | |____resources

2. 建立文件 build.gradle

重点引入 spring-boot-starter-security 依赖项，完整的 gradle 配置以下:

plugins {
    id 'java'
    id "io.spring.dependency-management" version "1.0.8.RELEASE"
}

group 'net.txt100.learn'
version '1.0'

sourceCompatibility = 1.8

apply plugin: 'application'
mainClassName = 'net.txt100.learn.springsecurity.base.case1.Case1Application'

repositories {
    maven {
        url "http://maven.aliyun.com/nexus/content/groups/public"
    }
    mavenCentral()
}

dependencyManagement {
    imports {
        mavenBom 'org.springframework.boot:spring-boot-dependencies:2.1.6.RELEASE'
    }
}

dependencies {
    testCompile group: 'junit', name: 'junit', version: '4.12'
    // spring boot
    compile group: 'org.springframework.boot', name: 'spring-boot-starter-web'
    compile group: 'org.springframework.boot', name: 'spring-boot-starter-security'
}

3. 建立一个资源服务 UserController.java

package net.txt100.learn.springsecurity.base.case1.controller;

import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;

/**
 * Title: UserController
 * Package: net.txt100.learn.springsecurity.base.case1.controller
 * Creation date: 2019-08-08
 * Description:
 *
 * @author <a href="me@tonglei.win">Tonglei</a>
 * @since 1.0
 */
@RestController
@RequestMapping("/user")
public class UserController {

    @RequestMapping("/all")
    public String getAllUsers() {
        return "这是一个被保护的资源 /user/all";
    }
}

4. 建立 spring-boot 启动类 Case1Application.java

package net.txt100.learn.springsecurity.base.case1;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

/**
 * @author <a href="mailto:me@tonglei.win">Tonglei</a>
 * @since 1.0
 */
@SpringBootApplication
public class Case1Application {
    public static void main(String[] args) {
        SpringApplication.run(Case1Application.class, args);
    }
}

5. 编译及执行

打开命令行，进入工程根目录，执行编译命令

gradle compileJava

执行运行命令

gradle run

访问 http://localhost:8080/user/all

此时浏览器显示以下

用户名填入 user

密码每次启动时自动生成，能够在日志中找到

...
2019-08-08 15:13:10.028 INFO 824 --- [ main] .s.s.UserDetailsServiceAutoConfiguration :
Using generated security password: 8c20d4a7-7507-41ce-a271-a75fbe0c7dee

认证经过后，可看到 User 控制器返回内容

总结

最简单的 spring-security 项目只须要在项目依赖中增长 spring-boot-starter-security 便可。

默认状况下，该项目的全部资源地址均需认证成功后才能访问。默认帐户 user，密码可从日志中找到。

若是想取消默认的安全设置，须要在配置文件中增长如下内容:

security.basic.enabled = false # 默认禁用 spring-security 安全配置