MetaClass

  它的做用主要是 指定由谁来建立类,默认是typepython

#python3
class Foo(metaclass=MyType):
    pass


#python2
class Foo(object):
    __metaclass__ = MyType

   注意下面的代码中的运行结果,若是某个基类执行谁来建立,那么继承这个基类的派生类也由这个谁来建立函数

class MyType(type):
    def __init__(self,*args,**kwargs):
        print('init')
        super(MyType, self).__init__(*args, **kwargs)

    def __call__(self, *args, **kwargs):
        print('call本质:调用类的__new__,在调用init方法')
        return super(MyType, self).__call__(*args, **kwargs)

class Foo(metaclass=MyType):
    def __call__(self, *args, **kwargs):
        print('123')

class Bar(Foo):
    pass

Foo()  #实例化对象,会执行负责建立类的type里的__call__方法
obj = Bar()
obj()  #对象+() 执行父类的里__call__方法

   应该见过这样建立类的吧,经过type建立Base = type('Base', (object,), {})spa

  因此咱们经过继承type的自定义type类也是能够这么作的Base = MyType('Base', (object,), {}),那这个过程本质也就是和上面metaclass同样的效果,指定了MyType进行建立类对象

class MyType(type):
    def __init__(self, *args, **kwargs):
        super(MyType, self).__init__(*args, **kwargs)

    def __call__(cls, *args, **kwargs):
        print('xxxx')
        return super(MyType, cls).__call__(*args, **kwargs)


# Base = MyType('Base', (object,), {})

# MyType('Base', (object,), {}) 是有MyType建立; metaclass=MyType
# 1. type能够建立类metaclass=type;MyType也能够建立类metaclass=MyType
# 2. Base = MyType('Base', (object,), {}) -->
# class Base(metaclass=MyType):
#     pass
# class Foo(Base):
#     pass

class Foo(MyType('Base', (object,), {})):
    pass
obj = Foo()

   因此这个Foo继承的是MyType建立的类,而Foo子类也会由MyType进行建立,彷佛这种方式看起更简洁blog

  不过把建立Base类型整个过程都写在Foo继承上,不免有些看着有些糟心,另外base执行继承类也是写死了,咱们可独立出一个函数进行封装,并动态实现传入继承类继承

class MyType(type):
    def __init__(self, *args, **kwargs):
        super(MyType, self).__init__(*args, **kwargs)

    def __call__(cls, *args, **kwargs):
        return super(MyType, cls).__call__(*args, **kwargs)


def with_metaclass(base):
    return MyType('XX', (base,), {})


class Foo(with_metaclass(object)):
    pass
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