它的做用主要是 指定由谁来建立类,默认是typepython
#python3 class Foo(metaclass=MyType): pass #python2 class Foo(object): __metaclass__ = MyType
注意下面的代码中的运行结果,若是某个基类执行谁来建立,那么继承这个基类的派生类也由这个谁来建立函数
class MyType(type): def __init__(self,*args,**kwargs): print('init') super(MyType, self).__init__(*args, **kwargs) def __call__(self, *args, **kwargs): print('call本质:调用类的__new__,在调用init方法') return super(MyType, self).__call__(*args, **kwargs) class Foo(metaclass=MyType): def __call__(self, *args, **kwargs): print('123') class Bar(Foo): pass Foo() #实例化对象,会执行负责建立类的type里的__call__方法 obj = Bar() obj() #对象+() 执行父类的里__call__方法
应该见过这样建立类的吧,经过type建立Base = type('Base', (object,), {})spa
因此咱们经过继承type的自定义type类也是能够这么作的Base = MyType('Base', (object,), {}),那这个过程本质也就是和上面metaclass同样的效果,指定了MyType进行建立类对象
class MyType(type): def __init__(self, *args, **kwargs): super(MyType, self).__init__(*args, **kwargs) def __call__(cls, *args, **kwargs): print('xxxx') return super(MyType, cls).__call__(*args, **kwargs) # Base = MyType('Base', (object,), {}) # MyType('Base', (object,), {}) 是有MyType建立; metaclass=MyType # 1. type能够建立类metaclass=type;MyType也能够建立类metaclass=MyType # 2. Base = MyType('Base', (object,), {}) --> # class Base(metaclass=MyType): # pass # class Foo(Base): # pass class Foo(MyType('Base', (object,), {})): pass obj = Foo()
因此这个Foo继承的是MyType建立的类,而Foo子类也会由MyType进行建立,彷佛这种方式看起更简洁blog
不过把建立Base类型整个过程都写在Foo继承上,不免有些看着有些糟心,另外base执行继承类也是写死了,咱们可独立出一个函数进行封装,并动态实现传入继承类继承
class MyType(type): def __init__(self, *args, **kwargs): super(MyType, self).__init__(*args, **kwargs) def __call__(cls, *args, **kwargs): return super(MyType, cls).__call__(*args, **kwargs) def with_metaclass(base): return MyType('XX', (base,), {}) class Foo(with_metaclass(object)): pass