Codeforces Round #519 by Botan Investments-E. Train Hard, Win Easy

时间 2021-07-11

标签算法繁體版

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地址：http://codeforces.com/contest/1043/problem/E 思路：排序+前缀和。对于取min(s1+ss2,s2+ss1),当 s1+ss2<s2+ss1即s1-s2<ss1-ss2取 s1+ss2,因此可以按照 s1-s2由小到大排序，再求得s1的前缀和ps1[n]和s2的后缀和ps2[n]。求出全部队员与其他队员组合的总和，对于第i位的队员，sum=a[i]

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1. [题解]Codeforces Round #519 - A. Elections
2. [题解]Codeforces Round #519 - B. Lost Array
3. [题解]Codeforces Round #519 - D. Mysterious Crime
4. [题解]Codeforces Round #519 - C. Smallest Word
5. Equalizing by Division (easy version)&&(hard version)
6. codeforces 1213D2 Equalizing by Division (hard version)
7. A. Vova and Train ( Codeforces Round #515 (Div. 3) )
8. Codeforces Round #555 (Div. 3) C2. Increasing Subsequence (hard version)
9. Codeforces Round #570 (Div. 3) G. Candy Box (hard version)
10. Codeforces Round #570 (Div. 3)D. Candy Box (easy version)

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