一段日期内星期都是周五的客流信息

-- 返回从beginDate到endDate，每小时的平均客流(group by 小时就可以了,sum(innum)/count(1)) SELECT TRUNCATE (SUM(rsh.innum) / COUNT(1), 2) AS innum, DATE_FORMAT(rsh.datatime, '%k:00') xstr FROM report_site_hour rsh WHERE r

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