selenium: 登陆QQ空间并破解滑块验证

 

1.引入Chrome驱动，打开qq空间网页

 

bro = webdriver.Chrome(executable_path='./chromedriver.exe') bro.get('https://qzone.qq.com/')

 

2.因为进入以后首先提示的是扫描二维码所以要切换到帐户密码登陆

 

　　首先找到帐户密码登陆所对应的标签

 

 　　以后触发点击 

a_tag = bro.find_element_by_id('switcher_plogin') a_tag.click()

　　

　　再以后找到帐户密码所对应的的input标签的id

userName_tag = bro.find_element_by_id('u') passWord_tag = bro.find_element_by_id('p')

 

三、输入帐户密码

 

userName_tag.send_keys("7xxxxx") passWord_tag.send_keys('xxxxx.')

 

4.找到登陆按钮所对应的的标签id

 

btn = bro.find_element_by_id("login_button") btn.click()

 

5.点击登陆后会切换到滑动验证窗口，这个验证窗口是嵌套在iframe标签里，所以须要先切换到验证框所对应的的iframe标签

iframe = bro.find_element_by_xpath('//iframe')  # 找到“嵌套”的iframe，开头//表示从当前节点寻找全部的后代元素，当前在iframe 须要往下嵌套的iframe
bro.switch_to.frame(iframe)  # 切换到iframe

 

　　拖动距离的能够经过拖动滑块观察下图中所示数值减去初始值来肯定距离

button = bro.find_element_by_id('tcaptcha_drag_button')  # 寻找滑块
print("寻找滑块")

sleep(1)

print("开始拖动")
# 开始拖动 perform()用来执行ActionChains中存储的行为
distance = 175
action = ActionChains(bro)
action.reset_actions()  # 清除以前的action
action.click_and_hold(button).perform()  # click_and_hold 点击并保持
action.move_by_offset(distance, 0).perform()
action.release().perform() # 释放action

 

6.完整代码:

from selenium import webdriver from time import sleep from selenium.webdriver import ActionChains bro = webdriver.Chrome(executable_path='./chromedriver.exe') bro.get('https://qzone.qq.com/') bro.switch_to.frame('login_frame') a_tag = bro.find_element_by_id('switcher_plogin') a_tag.click() userName_tag = bro.find_element_by_id('u') passWord_tag = bro.find_element_by_id('p') sleep(1) userName_tag.send_keys("7xxxxx") sleep(1) passWord_tag.send_keys('xxxxx.') btn = bro.find_element_by_id("login_button") btn.click() sleep(1) iframe = bro.find_element_by_xpath('//*[@id="tcaptcha_iframe"]')  # 找到“嵌套”的iframe
bro.switch_to.frame(iframe)  # 切换到iframe
sleep(2) button = bro.find_element_by_id('tcaptcha_drag_button')  # 寻找滑块
print("寻找滑块") sleep(1) print("开始拖动") # 开始拖动 perform()用来执行ActionChains中存储的行为
distance = 175 action = ActionChains(bro) action.reset_actions() # 清除以前的action
action.click_and_hold(button).perform()  # click_and_hold 点击并保持
action.move_by_offset(distance, 0).perform() action.release().perform() # 释放action
sleep(60) # 退出浏览器
bro.quit()

 

原文出处：https://www.cnblogs.com/kakawith/p/12395027.html