乘数加密解密

//功能:乘数加密 K=3 5 7 9 11 15 17 19 21 23 25 函数

#include <stdio.h>
int str_len(char *str)//求字符串的长度
{
 int len = 0;
 while(*(str++))
  len++;
 return len;
}
int main(int argc, char *argv[])
{
 char a[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
 char b[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
 char str[50];
 int k;
 printf("Please input the words(必须是小写能够用函数改变) :");
 gets(str);
 printf("Please input the following number[3][5][9][11][15][17][19][21][23]:");//能够求逆元的数
  scanf("%d",&k);
 int len = str_len(str);
 for(int i = 0;i<len;i++)
  for(int j = 0;j<26;j++)
  {
   if(str[i]==a[j])
    str[i] = b[(k*j)%26]//换
   else
    str[i] = str[i];//将空格等符号落下来
   }
  printf("%s\n",str);//打印
 return 0;
} 加密

//解密 调试

#include <stdio.h> 字符串

求字符串长度
int str_len(char *str)
{
 int len = 0;
 while(*(str++))
  len++;
 return len;
} get

//求逆元
int mulny(int k)
{
 int t;
 for(int i = 0;i<26;i++)
 {
  t=k*i;
  if(t%26==1)
   return i;
 }
} input

int main(int argc, char *argv[])
{
 char a[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
 char b[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
 char str[50];
 int k;
 printf("Please input the words :");
 gets(str);
 printf("Please input the following number[3][5][9][11][15][17][19][21][23]:");//26之内有逆元的数字
 scanf("%d",&k);
 int p = mulny(k);
 int len = str_len(str);
 for(int i = 0;i<len;i++)
  for(int j = 0;j<26;j++)
  {
   if(str[i]==a[j])
    str[i] = b[(p*j)%26];
   else
    str[i] = str[i];
  }
  printf("%s\n",str);
 return 0;
} io

/*
会凯撒加密的这个应该没啥大问题,可是刚刚玩,我调试仍是调试了一会的,我记得昨天都调好了,今天加密找不到了,存储代码的时候没规律。哎哎,又改的幸亏不费劲。也许有错的地方但愿提出改正,我想进步哦!谢谢你们。 gc

 

*/ word

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