Implement regular expression matching with support for ‘.’ and ‘*’. ‘.’ Matches any single character. ‘*’ Matches zero or more of the preceding element.The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p)
Some examples:
isMatch(“aa”,”a”) → false
isMatch(“aa”,”aa”) → true
isMatch(“aaa”,”aa”) → false
isMatch(“aa”, “a*”) → true
isMatch(“aa”, “.*”) → true
isMatch(“ab”, “.*”) → true
isMatch(“aab”, “c*a*b”) → truehtml
实现一个正则表达式匹配算法,.匹配任意一个字符,*匹配0个或者多个前导字符java
使用标记匹配算法法,从后向前进行匹配。正则表达式
import java.util.Arrays; public class Solution { /** * 010-Regular Expresssion Matching(正则表达式匹配) * * @param s 匹配串 * @param p 模式串 * @return 匹配结果,true匹配,false不匹配 */ public boolean isMatch(String s, String p) { // 标记数数组 boolean[] match = new boolean[s.length() + 1]; // 初始化 Arrays.fill(match, false); // 假定最后的结果是匹配的 match[s.length()] = true; // 对模式串从后向前进行处理 for (int i = p.length() - 1; i >= 0; i--) { // 若是当前是* if (p.charAt(i) == '*') { // 匹配串从最后一个开始处理 for (int j = s.length() - 1; j >= 0; j--) { match[j] = match[j] || match[j + 1] && (p.charAt(i - 1) == '.' || s.charAt(j) == p.charAt(i - 1)); } i--; } // 若是不是* else { for (int j = 0; j < s.length(); j++) { match[j] = match[j + 1] && (p.charAt(i) == '.' || p.charAt(i) == s.charAt(j)); } match[s.length()] = false; } } return match[0]; } }
import java.util.ArrayList;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class test {
public static void main(String[] args) {
getStrings(); //用正则表达式获取指定字符串内容中的指定内容
System.out.println("********************");
replace(); //用正则表达式替换字符串内容
System.out.println("********************");
strSplit(); //使用正则表达式切割字符串
System.out.println("********************");
strMatch(); //字符串匹配
}
private static void strMatch() {
String phone = "13539770000";
//检查phone是不是合格的手机号(标准:1开头,第二位为3,5,8,后9位为任意数字)
System.out.println(phone + ":" + phone.matches("1[358][0-9]{9,9}")); //true
String str = "abcd12345efghijklmn";
//检查str中间是否包含12345
System.out.println(str + ":" + str.matches("\\w+12345\\w+")); //true
System.out.println(str + ":" + str.matches("\\w+123456\\w+")); //false
}
private static void strSplit() {
String str = "asfasf.sdfsaf.sdfsdfas.asdfasfdasfd.wrqwrwqer.asfsafasf.safgfdgdsg";
String[] strs = str.split("\\.");
for (String s : strs){
System.out.println(s);
}
}
private static void getStrings() {
String str = "rrwerqq84461376qqasfdasdfrrwerqq84461377qqasfdasdaa654645aafrrwerqq84461378qqasfdaa654646aaasdfrrwerqq84461379qqasfdasdfrrwerqq84461376qqasfdasdf";
Pattern p = Pattern.compile("qq(.*?)qq");
Matcher m = p.matcher(str);
ArrayList<String> strs = new ArrayList<String>();
while (m.find()) {
strs.add(m.group(1));
}
for (String s : strs){
System.out.println(s);
}
}
private static void replace() {
String str = "asfas5fsaf5s4fs6af.sdaf.asf.wqre.qwr.fdsf.asf.asf.asf";
//将字符串中的.替换成_,由于.是特殊字符,因此要用\.表达,又由于\是特殊字符,因此要用\\.来表达.
str = str.replaceAll("\\.", "_");
System.out.println(str);
}
}算法
参考:express
http://www.thinksaas.cn/topics/0/102/102194.html数组
http://www.cnblogs.com/playing/archive/2011/03/15/1984943.htmlspa