MYSQL数据去重与外表填充

常常要对数据库中的数据进行去重，有时还须要使用外部表填冲数据，本文档记录数据去重与外表填充数据。
date：2016/8/17
author:wangxl

1 需求

对user_info1表去重，并添加age项。

2 表数据

user_info1:
+----+----------+------+------+
| id | name     | sex  | age  |
+----+----------+------+------+
|  1 | xiaolong | 1    | NULL |
|  2 | xiaoyun  | 1    | NULL |
|  3 | xiaoqin  | 2    | NULL |
|  4 | xiaolong | 1    | NULL |
|  5 | xiaodong | 1    | NULL |
|  6 | xiaokai  | 1    | NULL |
|  7 | xiaohong | 2    | NULL |
|  8 | xiaolong | 1    | NULL |
|  9 | xiaohong | 2    | NULL |
| 10 | xiaofen  | 2    | NULL |
+----+----------+------+------+

user_info2:
+----------+------+
| name     | age  |
+----------+------+
| xiaolong |   26 |
| xiaoyun  |   28 |
| xiaoqin  |   27 |
| xiaodong |   27 |
| xiaokai  |   27 |
| xiaohong |   24 |
| xiaofen  |   22 |
+----------+------+

3 实战

3.1 去重

(1) 找出有重复字段
    select * from user_info1 where name in (select name from user_info1 group by name having count(name) > 1);
(2) 找出要删除的记录，重复记录是根据单个字段（name）来判断，只留有id最小的记录
    select * from user_info1 where name in (select name from user_info1 group by name having count(name) > 1) and id not in (select min(id) from user_info1 group by name having count(name) > 1);
(3) 删除表中多余的重复记录
    delete from user_info1 where name in (select name from user_info1 group by name having count(name) > 1) and id not in (select min(id) from user_info1 group by name having count(name) > 1);

    报错：ERROR 1093 (HY000): You can't specify target table 'user_info1' for update in FROM clause

更换思路：找出每组中非最小id并删除,以下：

(4) 找出每组最小id
    select min(id) from user_info1 group by name
(5) 找出每组非最小id
    select * from user_info1 where id not in (select min(id) from user_info1 group by name);
(6) 删除每组中非最小id所在行
    delete from user_info1 where id not in (select id from select min(id) from user_info1 group by name);
    ERROR 1093 (HY000): You can't specify target table 'user_info1' for update in FROM clause
    更正：
    delete from user_info1 where id not in (select minid from (select min(id) as minid from user_info1 group by name) a);、

结果展现：
+----+----------+------+------+
| id | name     | sex  | age  |
+----+----------+------+------+
| 1  | xiaolong | 1    | NULL |
| 2  | xiaoyun  | 1    | NULL |
| 3  | xiaoqin  | 2    | NULL |
| 5  | xiaodong | 1    | NULL |
| 6  | xiaokai  | 1    | NULL |
| 7  | xiaohong | 2    | NULL |
| 10 | xiaofen  | 2    | NULL |
+----+----------+------+------+

对于没有primary key的话，怎么去重呢？

(7) 建立表test
(8) insert into test select distinct(name),sex,age from user_info1 group by name; 

暂时没想出一句话解决方案.

3.2 外表插入

update user_info1 t set age=(select age from user_info2 where name=t.name);
结果以下：
+----+----------+------+------+
| id | name     | sex  | age  |
+----+----------+------+------+
| 1  | xiaolong | 1    |   26 |
| 2  | xiaoyun  | 1    |   28 |
| 3  | xiaoqin  | 2    |   27 |
| 5  | xiaodong | 1    |   27 |
| 6  | xiaokai  | 1    |   27 |
| 7  | xiaohong | 2    |   24 |
| 10 | xiaofen  | 2    |   22 |
+----+----------+------+------+