select count(*) + 1 as count from top where `status`= 0 and `day` = '144022222' and `count` > '本身分享个数'
缺点:当多个用户分享个数相同的时候,会出现排名相同的状况post
在网上找了再三,经过比较,确认了如下的方法是可行的 :spa
SELECT @rownum:=@rownum+1 rownum, CollectSn From (SELECT @rownum:=0,bbgmain.* FROM qbdb.bbgmain WHERE collectsn!='' ORDER BY collectsn limit 10) t
按照点击数排序,查询new表里的文章排名code
select * from ( select @rank:=@rank+1 as rank, id, title from (select @rank:=0, news.* from news order by dian_num desc) rank) news_rank where id = 4;