假设有两种表:test_on_position表和address表,address表存放地址,test_on_position存放会员及其经常使用的地址,数据以下:3d
address表:code
test_on_position表:blog
SELECT * FROM test_on_position LEFT JOIN address ON test_on_position.address = address.id WHERE test_on_position.address IS NOT NULL
运行结果:it
SELECT * FROM test_on_position LEFT JOIN address ON test_on_position.address = address.id AND test_on_position.address IS NOT NULL
运行结果:io
当条件放在on后面时,不管on条件的真假,都会返回左表的值;test
当条件放在where后面时,只有知足条件的记录会返回。im
SELECT * FROM test_on_position INNER JOIN address ON test_on_position.address = address.id AND test_on_position.address IS NOT NULL
运行结果:d3
SELECT * FROM test_on_position INNER JOIN address ON test_on_position.address = address.id WHERE test_on_position.address IS NOT NULL
运行结果:数据
不管条件放在哪里,都只会返回知足条件的结果。db