MySQL中条件放在where后面与放在on后面的区别

假设有两种表:test_on_position表和address表,address表存放地址,test_on_position存放会员及其经常使用的地址,数据以下:3d

address表:code

test_on_position表:blog

1. left join

条件在where后面

SELECT
    *
FROM
    test_on_position
LEFT JOIN address ON test_on_position.address = address.id
WHERE
    test_on_position.address IS NOT NULL

运行结果:it

条件在on后面

SELECT
    *
FROM
    test_on_position
LEFT JOIN address ON test_on_position.address = address.id AND test_on_position.address IS NOT NULL

运行结果:io

结果分析

当条件放在on后面时,不管on条件的真假,都会返回左表的值;test

当条件放在where后面时,只有知足条件的记录会返回。im

inner join

条件在on后面

SELECT
    *
FROM
    test_on_position
INNER JOIN address ON test_on_position.address = address.id AND test_on_position.address IS NOT NULL

运行结果:d3

条件在where后面

SELECT
    *
FROM
    test_on_position
INNER JOIN address ON test_on_position.address = address.id
WHERE
    test_on_position.address IS NOT NULL

运行结果:数据

结果分析

不管条件放在哪里,都只会返回知足条件的结果。db

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