mysql 查询近7天数据，缺失补0

相信不少人的项目都有这种需求，就是查询近7天的记录，可是这7天总有那么几天是没数据的，因此缺失的只能补 0 

下面的代码不知道能不能看懂，我简单的说一下思路

1）先查询红色字体的近7天，再转换成日期

2）个人字段使用的是时间戳的方式去保存，只能是先数据库字段先转日期

2.1）先查询本身想要的数据，用天天分组，计算好总数后

2.2）时间戳字段先转日期

2.3）用 ifnull 函数判断，缺失就补 0 

而后~~~~而后就大功告成啦

select temp.days, ifnull(walletTemp.money, 0) as money from (
SELECT curdate() as days
union all
SELECT date_sub(curdate(), interval 1 day) as days
union all
SELECT date_sub(curdate(), interval 2 day) as days
union all
SELECT date_sub(curdate(), interval 3 day) as days
union all
SELECT date_sub(curdate(), interval 4 day) as days
union all
SELECT date_sub(curdate(), interval 5 day) as days
union all
SELECT date_sub(curdate(), interval 6 day) as days ) as temp
left join
(select date(FROM_UNIXTIME(createAt, '%Y%m%d')) as datetime, sum(money) as money
from wb_car_wallet where driverId = 'e472e99da1be45918c82d92753382ac3'
and type = 0 or type = 1
group by from_unixtime(createAt, '%Y-%m-%d')
order by createAt) as walletTemp on temp.days = walletTemp.datetime