shell脚本——循环和函数

一、打印一个等腰三角形linux

#!/bin/bash
for i in `seq 10` ;do
    for j in `seq $[10-$i]` ;do
        echo -n ' '
    done

    for k in `seq $[i*2-1]` ;do
        echo -n '*'
    done
    echo
done

二、打印99乘法表bash

#!/bin/bash for i in {1..9} ;do
    for (( j=1; j<=$i; j++ )) ;do accumulate=$[i*j] echo -ne "${j}*${i}=$accumulate\t"
    done
    echo
done

三、输入网段，探测网段内存活的主机函数

#!/bin/bash trap 'exit' 2 read -p "please input a network address: " DNET echo $DNET |grep -qE "^([1-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-4])\.(([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-4])\.){2}0$" || { echo "ipaddr error"; exit; } for I in {1..254} ;do { if ping -W1 -c1 ${DNET%.*}.$I &>/dev/null ;then
    echo "${DNET%.*}.$I is up."
  fi }&
done unset DNET unset I wait

四、打印国际象棋棋盘学习

#!/bin/bash read -p "size: " bsize line=$[bsize*8-1] for i in `seq 0 $line` ;do
    for j in `seq 0 $line` ;do
        if [ $[(i/bsize+j/bsize)%2] -eq 0 ] ;then
            echo -ne "\033[47m \033[0m"
        else
            echo -n "  "
        fi
    done
    echo
done

五、编写函数(my_functions)，实现打印绿色OK和红色FAILEDui

#Print OK and FAILED####################################### green_OK() { echo -e "[ \033[1;32mOK\033[0m ]"; } red_FAILED() { echo -e  "[ \033[1;31mFAILED\033[0m ]"; } Screen=`stty -F /dev/tty size` Columus=${Screen#* } Spa_Col=$[Columus-26] Progress() { local i for i in {1..3} ;do
                echo -n "."
                sleep 0.5
        done } success() { local i string="$1" Rt_Spa=$[$Spa_Col-${#string}] echo -n "$string" Progress for i in `seq $Rt_Spa` ;do
                echo -n " "
        done green_OK } failed() { local i string="$1" Rt_Spa=$[$Spa_Col-${#string}] echo -n "$string" Progress for i in `seq $Rt_Spa` ;do
                echo -n " "
        done red_FAILED }

六、编写脚本copycmd.shspa

(1) 提示用户输入一个可执行命令名称;
(2) 获取此命令所依赖到的全部库文件列表;
(3) 复制命令至某目标目录(例如/mnt/sysroot)下的对应路径下;
- 如：/bin/bash ==> /mnt/sysroot/bin/bash
(4) 复制此命令依赖到的全部库文件至目标目录下的对应路径下;
- 如：/lib64/ld-linux-x86-64.so.2 ==> /mnt/sysroot/lib64/ld-linux-x86-64.so.2
(5)每次复制完成一个命令后，不要退出，而是提示用户键入新的要复制的命令，并重复完成上述功能；直到用户输入quit退出;

#!/bin/bash . my_functions Ddir="/mnt/sysroot" [ ! -d "$Ddir" ] && mkdir "$Ddir" cpbin() { cmddir=`echo "$Cmd_path" |grep -o ".*/\b"` [ ! -d "${Ddir}${cmddir}" ] && mkdir -p "${Ddir}${cmddir}"
        cp -n "$Cmd_path" "${Ddir}${cmddir}" } libcp() { echo "$Lib_path" |while read line ;do libdir=`echo "$line" |grep -o ".*/\b"` [ ! -d "${Ddir}${libdir}" ] && mkdir -p "${Ddir}${libdir}"
                cp -n "$line" "${Ddir}${libdir}" 2>/dev/null
        done } while read -p "Input a cmd. (quit): " CMD ;do
        if [ "$CMD" == 'quit' ] ;then echo "Think you! Bye bye."; break; fi
        if ! which "$CMD" &>/dev/null ;then 
                echo "not find $CMD, please input again." failed "copy $CMD failed." continue fi Cmd_path=`which $CMD |grep -o "/.*"` Lib_path=`ldd $Cmd_path |sed -nr 's#.*[[:space:]]+(/.*) .*#\1#p'` cpbin libcp success "copy $CMD Complete."
done

七、求斐波那契数列的第N个数rest

#!/bin/bash feibo() { if [ $1 -eq 0 ] ; then
        echo 0
    elif [ $1 -eq 1 ] ;then
        echo 1
    else
        echo $[`feibo $[$1-1]`+`feibo $[$1-2]`] fi } read -p "please a num: " n

八、求N的阶乘code

#!/bin/bash fact() { if [ $1 -eq 0 -o $1 -eq 1 ] ;then
                echo 1
        else
                echo $[$1*`fact $[$1-1]`] fi } fact $1

九、汉诺塔：问题是源于印度一个古老传说。大梵天创造世界的时候作了三根金刚石柱子，在一根柱子上从下往上按照大小顺序摞着64片黄金圆盘。大梵天命令婆罗门把圆盘从下面开始按大小顺序从新摆放在另外一根柱子上。而且规定，在小圆盘上不能放大圆盘，在三根柱子之间一次只能移动一个圆盘，利用函数，实现N片盘的汉诺塔的移动步骤。blog

hannuota() { local from=$2 local buffer=$3 local to=$4 local m=$1

        if [ "$m" -eq 1 ] ;then
                echo "$from --> $to"
        else hannuota $[m-1] $from $to $buffer echo "$from --> $to" hannuota $[m-1] $buffer $from $to fi } read -p "please input num: " n hannuota $n a b c

十、编写服务脚本testsrv.sh，完成以下要求ip

(1) 脚本可接受参数：start, stop, restart, status
(2) 若是参数非此四者之一，提示使用格式后报错退出
(3) 如是start:则建立/var/lock/subsys/SCRIPT_NAME, 并显示“启动成功”
- 考虑：若是事先已经启动过一次，该如何处理？
(4) 如是stop:则删除/var/lock/subsys/SCRIPT_NAME, 并显示“中止完成”
- 考虑：若是事先已然中止过了，该如何处理？
(5) 如是restart，则先stop, 再start
- 考虑：若是原本没有start，如何处理？
(6) 如是status, 则若是/var/lock/subsys/SCRIPT_NAME文件存在，则显示“SCRIPT_NAME is running...” 若是/var/lock/subsys/SCRIPT_NAME文件不存在，则显示“SCRIPT_NAME is stopped...” 其中：SCRIPT_NAME为当前脚本名
(7)在全部模式下禁止启动该服务，可用chkconfig 和 service命令管理

#!/bin/bash
# chkconfig: 2345 98 01 . /root/bin/35_my_functions lockfile="/var/lock/subsys/testsrv" s_start() { [ -f "$lockfile" ] && failed "testsrv is running." && exit touch "$lockfile" success "testsrv start " } s_stop() { [ ! -f "$lockfile" ] && failed "testsrv is not running." && exit rm -f "$lockfile" success "testsrv stop " } s_status() { [ -f "$lockfile" ] && echo "testsrv is running." || echo "testsrv is not running." } s_usage() { echo "Usage: `basename $0` {start|stop|restart|status}" exit 1 } [ $# -ne 1 ] && s_usage case $1 in start) s_start ;; stop) s_stop ;; restart) if [ -f "$lockfile" ] ;then s_stop s_start else failed "testsrv is not running , stop " s_start fi ;; status) s_status ;; *) s_usage esac

我的学习笔记，只供参考 ^_^