leetcode 16 3Sum Closest

题目详情

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

给定一个整数数组，咱们须要找出数组中三个元素的加和，使这个加和最接近于输入的target数值。返回这个最接近的加和。题目假设一道题只有一个答案。

For example,输入数组S = {-1 2 1 -4},目标和target = 1.
最接近target的加和是 2. (-1 + 2 + 1 = 2).

想法

• 这道题和第15题很像，因此这道题也能够选择预排序算法。
• 咱们先对数组进行预排序。
• 而后经过减治思想，咱们先锁定第一个元素，以后找两个元素的加和尽量接近target和第一个元素值的差值。
• 找后两个元素的时候，使用左右指针从两端查找。

解法

public int threeSumClosest(int[] nums, int target) {
        int min = Integer.MAX_VALUE;
        Arrays.sort(nums);
        
        for(int i=0;i<nums.length-2;i++){
            int temp = target - nums[i];
            int low = i+1;
            int high = nums.length-1;           
            while(low < high){
                int diff =   nums[low]+nums[high]-temp;
                if(diff == 0) return target;
                if(Math.abs(min) > Math.abs(diff)){
                    min = diff;
                    }
                if(diff > 0)high--;
                else low++;
                    
            }
        }
        
        return target+min;
    }