连接:https://leetcode.com/problems...java
Given an array A of positive lengths, return the largest perimeter of a triangle with non-zero area, formed from 3 of these lengths.code
If it is impossible to form any triangle of non-zero area, return 0.orm
Example 1:排序
Input: [2,1,2] Output: 5
Example 2:leetcode
Input: [1,2,1] Output: 0
Example 3:get
Input: [3,2,3,4] Output: 10
Example 4:it
Input: [3,6,2,3] Output: 8
Note:
3 <= A.length <= 10000
1 <= A[i] <= 10^6form
一个面积不为空的三角形,那么必需要最小的两条边之和大于第三边,才能构成一个三角形。而且要周长最大。很容易想到,先对数据进行排序,从最大的开始进行筛选,像窗口同样,往左侧移动,一旦找到符合条件的三角形,就是面积最大的。class
public int largestPerimeter(int[] A) { Arrays.sort(A); for (int i = A.length - 3; i >= 0; i--) { if (A[i] + A[i + 1] > A[i + 2]) { return A[i] + A[i + 1] + A[i + 2]; } } return 0; }