Python-判断列表（list)是否为空

1.其余表对比判断 列表不为空：code list_1 = [1,2] list_2 = [] if list_1 != list_2: print('list is not none')  列表为空：class list_1 = [] list_2 = [] if list_1==list_2: print('list_1 is none') 2.if 列表判断 列表不为空（空列

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