mysql基础 依据一个字段查询另外一个字段存在不同的值

原数据 需求：查询出存在不同year的人 SELECT s1.* FROM `score` s1 where exists(SELECT 1 FROM score s2 where s2.id != s1.id AND s2.`name` = s1.`name` AND s2.`year` != s1.`year`); 或者SELECT DISTINCT s.* from score s,scor

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