在n条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复并保留一条呢?方法以下:code
一、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断it
select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
二、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录select
delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
三、查找表中多余的重复记录(多个字段)方法
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
四、删除表中多余的重复记录(多个字段),只留有rowid最小的记录vi
delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
五、查找表中多余的重复记录(多个字段),不包含rowid最小的记录co
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)