谷歌浏览器chrome console 发送POST/GET请求

打开chrome 开发者工具
登陆你访问的系统，复制你后台系统提供的url
在Console中输入以下代码 可发送http post/get请求

POST请求：

//方法一：
var url = "/dict/test"; var params = {advertiserUid: 1232131, advertiserWeiboNickname: "18"}; var xhr = new XMLHttpRequest(); xhr.open("POST", url, true); xhr.setRequestHeader("Content-Type", "application/json"); xhr.onload = function (e) { if (xhr.readyState === 4) { if (xhr.status === 200) { console.log(xhr.responseText); } else { console.error(xhr.statusText); } } }; xhr.onerror = function (e) { console.error(xhr.statusText); }; xhr.send(JSON.stringify(params)); //方法二：
var url = "/dict/test"; var params = "score=5&abc=6"; var xhr = new XMLHttpRequest(); xhr.open("POST", url, true); xhr.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xhr.onload = function (e) { if (xhr.readyState === 4) { if (xhr.status === 200) { console.log(xhr.responseText); } else { console.error(xhr.statusText); } } }; xhr.onerror = function (e) { console.error(xhr.statusText); }; xhr.send(params);

 

GET请求：

 1 var url = "/v1/query/listDicts?types=userType,userStatus";  2 var xhr = new XMLHttpRequest();  3 xhr.open("GET", url, true);  4 xhr.onload = function (e) {  5   if (xhr.readyState === 4) {  6     if (xhr.status === 200) {  7  console.log(xhr.responseText);  8     } else {  9  console.error(xhr.statusText); 10  } 11  } 12 }; 13 xhr.onerror = function (e) { 14  console.error(xhr.statusText); 15 }; 16 xhr.send(null);