C++11 double转化为string

C++11转化double为string是一件很容易的事情。ios

 

方法:

1:使用C中的sprintf函数,这里就不说了。git

2:使用std::ostringstream。这个与std::cout是同样的。这个在C++11之前就已经支持了的。这个得出的结果与使用std::cout的结果是同样的。ide

3:从C++11开始,标准库提供了std::to_string辅助函数转化各种型为一个字符串。函数

 

std::ostringstream和std::to_string

可是std::ostringstream和std::to_string使用的结果就有些很奇怪的差别了。主要有:性能

1:std::string获得的结果始终是小数位必然是6!测试

2:默认状况下,std::ostringstream对double使用的是6位精度。这里精度值的是整数位和小数位个数和。可是精度是能够设置的。这里统一谈论默认的状况。spa

也就是说,若是参数精度超过6位的话,那么会将数值四舍五入,而后丢弃多余的位数!
具体来讲是这样的:code

1:若是整数位不足6位,而总体精度超过了6,那么小数位四舍五入,而后截断多余的位数。blog

2:若是是整数位超过了6,那么舍弃小数位,而后按照科学计数法保存。ci

好比:

序号 double原值 std::ostringstream结果
1 1.0000000000001 1
2 0.12345678 0.123457
3 123456789.0000000000001 1.23457e+08
4 123456789.1234567 1.23457e+08
5 0.0000000000001 1e-13

 

 

 

 

 

 

 

 

 

下面咱们详细比较std::ostringstream和std::to_string使用的结果的差别。

这里是详细的测试代码,请注意,这里必须是C++11及以上版本!

 1     1 #include <string>                                                                                                                                                                                                                                                                                                      
 2     2 #include <cassert>
 3     3 #include <iostream>
 4     4 #include <sstream>
 5     5
 6     6 std::string DoubleToStringByStdToString(double value)
 7     7 {
 8 
 9     8     const std::string& new_val = std::to_string(value);
10     9     return new_val;
11    10  }
12    1113    12  std::string DoubleToStringByStringStream(double value)
14    13  {
15    14      std::ostringstream stream;
16    15      stream << value;
17    16      return stream.str();
18    17  }
19    1820    19  void TestDoubleToStringByStdToString(const double value, const std::string& origin, const std::string& expect_str)
21    20  {
22    21      const std::string& val = DoubleToStringByStdToString(value);
23    22      std::cout << __FUNCTION__ << " --> original:" << origin
24    23                                << ", std::cout:" << value
25    24                                << ", std::to_string:" << val<< std::endl;
26    2527    26      assert( val == expect_str);
28    27  }
29    2830    29  void TestDoubleToStringByStringStream(const double value, const std::string& origin, const std::string& expect_str)
31    30  {
32    31      const std::string& val = DoubleToStringByStringStream(value);
33    32      std::cout << __FUNCTION__ << " --> original:" << origin
34    33                                << ", std::cout:" << value
35    34                                << ", std::stringstream:" << val<< std::endl;
36    3537    36      assert( val == expect_str);
38    37  }
39    38
40    39 int main(int argc, char* argv[])
41    40 {
42    41     TestDoubleToStringByStdToString(0, "0", "0.000000");
43    42     TestDoubleToStringByStringStream(0, "0", "0");
44    43
45    44     TestDoubleToStringByStdToString(.0, ".0", "0.000000");
46    45     TestDoubleToStringByStringStream(.0, ".0", "0");
47    46
48    47     TestDoubleToStringByStdToString(0.0, "0.0", "0.000000");
49    48     TestDoubleToStringByStringStream(0.0, "0.0", "0");
50    49
51    50     TestDoubleToStringByStdToString(1.0, "1.0", "1.000000");
52    51     TestDoubleToStringByStringStream(1.0, "1.0", "1");
53    52
54    53     TestDoubleToStringByStdToString(1.0000008, "1.0000008", "1.000001");
55    54     TestDoubleToStringByStringStream(1.0000008, "1.0000008", "1");
56    55
57    56     TestDoubleToStringByStdToString(1.0000000000001,"1.0000000000001", "1.000000");
58    57     TestDoubleToStringByStringStream(1.0000000000001,"1.0000000000001", "1");
59    58
60    59     TestDoubleToStringByStdToString(0.0000000000001,"0.0000000000001", "0.000000");
61    60     TestDoubleToStringByStringStream(0.0000000000001,"0.0000000000001", "1e-13");
62    61
63    62     TestDoubleToStringByStdToString(0.12345678,"0.12345678", "0.123457");
64    63     TestDoubleToStringByStringStream(0.12345678,"0.12345678", "0.123457");
65    64
66    65     TestDoubleToStringByStdToString(100000000000.0000000000001,"100000000000.0000000000001", "100000000000.000000");
67    66     TestDoubleToStringByStringStream(100000000000.0000000000001,"100000000000.0000000000001", "1e+11");
68    67
69    68     TestDoubleToStringByStdToString(1e+11,"1e+11",  "100000000000.000000");
70    69     TestDoubleToStringByStringStream(1e+11,"1e+11",  "1e+11");
71    70
72    71     TestDoubleToStringByStdToString(123456.0000000000001, "123456.0000000000001", "123456.000000");
73    72     TestDoubleToStringByStringStream(123456.0000000000001, "123456.0000000000001", "123456");
74    73
75    74     TestDoubleToStringByStdToString(123456789.1234567,"123456789.1234567", "123456789.123457");
76    75     TestDoubleToStringByStringStream(123456789.1234567,"123456789.1234567", "1.23457e+08");
77    76
78    77     TestDoubleToStringByStdToString(123456789.0000000000001,"123456789.0000000000001", "123456789.000000");
79    78     TestDoubleToStringByStringStream(123456789.0000000000001,"123456789.0000000000001", "1.23457e+08");
80    79
81    80     return 0;
82    81 }
View Code

 

咱们这里将结果整理出来以下表

序号 double原值 std::cout std::ostringstream结果 std::to_string()结果
1 0 0 0 0.000000
2 .0 0 0 0.000000
3 0.0 0 0 0.000000
4 1.0 1 1 1.000000
5 1.0000008 1 1 1.000001
6 1.0000000000001 1 1 1.000000
7 0.0000000000001 1e-13 1e-13 0.000000
8 0.12345678 0.123457 0.123457 0.123457
9 100000000000.0000000000001 1e+11 1e+11 100000000000.000000
10 1e+11 1e+11 1e+11 100000000000.000000
11 123456.0000000000001 123456 123456 123456.000000
12 123456789.1234567 1.23457e+08 1.23457e+08 123456789.123457
13 123456789.0000000000001 1.23457e+08 1.23457e+08 123456789.000000

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

从上面的结果咱们还能够发现一个关于std::to_string的特色

若是传入的double自己是科学记数法,to_string仍然能够执行转化,且得出的结果与该科学技术法表述的值转化的结果是同样的!

 

总结

虽然C++对关转化double为string提供的方法不少,可是的得出的结果不同。因此在使用时应该统一方法,而且格外当心,若是是在对double很敏感的行业,那么应该对该操做封装,并提供足够的控制参数。

 

一种可参考的实现

从上面咱们能够看出使用ostringstream或者to_string的方法,要么存在精度显示问题要么调整为科学计数法显示。这些都不是咱们想要的。

因此咱们可使用ostringstream封装一个辅助函数,能够控制精度也能够控制科学计数法显示。

 

精度

ostringstream是能够控制精度的,函数原型以下:

std::ios_base::precision

 

初版

 1 std::string DoubleToString(const double value, unsigned int precision)                                                                                                                                                                                                          
 2 {
 3    std::ostringstream out;
 4    if (precision > 0)
 5        out.precision(precision);
 6 
 7    out << value;
 8    return out.str();
 9 }
10 
11 
12 int main(int argc, char* argv[])
13 {
14     std::cout << DoubleToString(0., 12) << std::endl;
15     std::cout << DoubleToString(0.0, 12) << std::endl;
16     std::cout << DoubleToString(.0, 12) << std::endl;
17     std::cout << DoubleToString(1.0, 12) << std::endl;
18     std::cout << DoubleToString(11234, 12) << std::endl;
19     std::cout << DoubleToString(0.12345, 12) << std::endl;
20     std::cout << DoubleToString(0.12345678, 12) << std::endl;
21     std::cout << DoubleToString(0.12345678, 9) << std::endl;
22     std::cout << DoubleToString(0.12345678, 8) << std::endl;
23     std::cout << DoubleToString(0.12345678, 6) << std::endl;
24     return 0;
25 }
View Code

这是测试结果的输出:

0
0
0
1
11234
0.12345
0.12345678
0.12345678
0.12345678
0.123457

 

第二版

多数状况下咱们更加关注的是小数点后的几位数,因此咱们调整参数控制小数点后位数。

 1 #include <limits>
 2 std::string DoubleToString(const double value, unsigned int precisionAfterPoint)
 3 {
 4    std::ostringstream out;
 5    // 清除默认精度
 6    out.precision(std::numeric_limits<double>::digits10);
 7    out << value;
 8 
 9    std::string res = std::move(out.str());
10    auto pos = res.find('.');
11    if (pos == std::string::npos)
12        return res;
13 
14    auto splitLen = pos + 1 + precisionAfterPoint;
15    if (res.size() <= splitLen)
16        return res;
17 
18    return res.substr(0, splitLen);
19 }
20 
21 int main(int argc, char* argv[])
22 {
23     std::cout << DoubleToString(0., 12) << std::endl;
24     std::cout << DoubleToString(0.0, 12) << std::endl;
25     std::cout << DoubleToString(.0, 12) << std::endl;
26     std::cout << DoubleToString(1.0, 12) << std::endl;
27     std::cout << DoubleToString(11234, 12) << std::endl;
28     std::cout << DoubleToString(12345.12345678, 12) << std::endl;
29     std::cout << DoubleToString(12345.12345678, 9) << std::endl;
30     std::cout << DoubleToString(12345.12345678, 7) << std::endl;
31     std::cout << DoubleToString(12345.12345678, 8) << std::endl;
32     std::cout << DoubleToString(12345.12345678, 6) << std::endl;
33     std::cout << DoubleToString(12345.00000001, 7) << std::endl;
34     std::cout << DoubleToString(12345.00000001, 8) << std::endl;
35     std::cout << DoubleToString(12345.00000001, 6) << std::endl;
36     return 0;
37 }
View Code

这是测试结果的输出:

0
0
0
1
11234
12345.12345678
12345.12345678
12345.1234567
12345.12345678
12345.123456
12345.0000000
12345.00000001
12345.000000

 

第三版

更进一步的,咱们通常默认状况下小数点后是是6位小数的。因此咱们能够设置默认参数:

 1 #include <limits>
 2 std::string DoubleToString(const double value, unsigned int precisionAfterPoint = 6)
 3 {
 4    std::ostringstream out;
 5    // 清除默认精度
 6    out.precision(std::numeric_limits<double>::digits10);
 7    out << value;
 8 
 9    std::string res = std::move(out.str());
10    auto pos = res.find('.');
11    if (pos == std::string::npos)
12        return res;
13 
14    auto splitLen = pos + 1 + precisionAfterPoint;
15    if (res.size() <= splitLen)
16        return res;
17 
18    return res.substr(0, splitLen);
19 }
View Code

 

第四版

1:实际上第三版的实现存在一个BUG,即设置默认小数位后没有执行四舍五入!

2:性能。这个实现性能如何,是否是存在更佳的实现呢?

3:处理完成后,若是小数位全是0,该怎么处理?

请读者本身去研究解决。

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