os.path.join()
函数功能:链接两个或更多的路径名组件函数
若是各组件名首字母不包含’/’,则函数会自动加上spa
若是有一个组件是一个绝对路径,则在它以前的全部组件均会被舍弃code
若是最后一个组件为空,则生成的路径以一个’/’分隔符结尾blog
import os Path1 = 'home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)
输出以下:class
Path10 = homedevelopcode
Path20 = home\develop\code
import os Path1 = '/home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)
输出以下:import
Path10 = /homedevelopcode
Path20 = /home\develop\code
import os Path1 = 'home' Path2 = '/develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)
输出以下:im
Path10 = home/developcode
Path20 = /develop\code
import os Path1 = 'home' Path2 = 'develop' Path3 = '/code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)
输出以下:di
Path10 = homedevelop/code
Path20 = /code