js小方法,获取知道公历生日 (‘1992-01-19’),获取阴历生日日期,属相,非简单根据年份判断-----------声明:整理自网络!!

 1 let lunar = {  2   tg: '甲乙丙丁戊己庚辛壬癸',  3   dz: '子丑寅卯辰巳午未申酉戌亥',  4   number: '一二三四五六七八九十',  5   year: '鼠牛虎兔龙蛇马羊猴鸡狗猪',  6   month: '正二三四五六七八九十冬腊',  7   monthadd: [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334],  8   calendar: [0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95],  9 }; 10 // 获取阴历日期
11 const getLunarDate = (date) => { 12   let useDate = new Date(); 13  let year, 14  month, 15  day; 16   if (!date) { 17     date = new Date(), year = date.getFullYear(), month = date.getMonth(), day = date.getDate(); 18   } else { 19     date = date.split('-'), year = parseInt(date[0]), month = date[1] - 1, day = parseInt(date[2]); 20  } 21 
22   if (year < 1921 || year > 2020) { 23     return {}; 24  } 25 
26  let total, 27  m, 28  n, 29  k, 30  bit, 31  lunarYear, 32  lunarMonth, 33  lunarDay; 34   let isEnd = false; 35   let tmp = year; 36   if (tmp < 1900) { 37     tmp += 1900; 38  } 39   total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + lunar.monthadd[month] + day - 38; 40   if (year % 4 == 0 && month > 1) { 41     total++; 42  } 43   for (m = 0; ; m++) { 44     k = (lunar.calendar[m] < 0xfff) ? 11 : 12; 45     for (n = k; n >= 0; n--) { 46       bit = (lunar.calendar[m] >> n) & 1; 47       if (total <= 29 + bit) { 48         isEnd = true; 49         break; 50  } 51       total = total - 29 - bit; 52  } 53     if (isEnd) break; 54  } 55   lunarYear = 1921 + m; 56   lunarMonth = k - n + 1; 57   lunarDay = total; 58   if (k == 12) { 59     if (lunarMonth == Math.floor(lunar.calendar[m] / 0x10000) + 1) { 60       lunarMonth = 1 - lunarMonth; 61  } 62     if (lunarMonth > Math.floor(lunar.calendar[m] / 0x10000) + 1) { 63       lunarMonth--; 64  } 65  } 66 
67   return { 68  lunarYear, 69  lunarMonth, 70  lunarDay, 71  }; 72 }; 73 
74 // 获取阴历年信息
75 const getLunarDateString = (lunarDate) => { 76   if (!lunarDate.lunarDay) return; 77   let data = {}; 78   let lunarYear = lunarDate.lunarYear; 79   let lunarMonth = lunarDate.lunarMonth; 80   let lunarDay = lunarDate.lunarDay; 81 
82   data.tg = lunar.tg.charAt((lunarYear - 4) % 10); 83   data.dz = lunar.dz.charAt((lunarYear - 4) % 12); 84   data.year = lunar.year.charAt((lunarYear - 4) % 12); 85   data.month = lunarMonth < 1 ? `(闰)${lunar.month.charAt(-lunarMonth - 1)}` : lunar.month.charAt(lunarMonth - 1); 86 
87   data.day = (lunarDay < 11) ? '初' : ((lunarDay < 20) ? '十' : ((lunarDay < 30) ? '廿' : '三十')); 88   if (lunarDay % 10 != 0 || lunarDay == 10) { 89     data.day += lunar.number.charAt((lunarDay - 1) % 10); 90  } 91 
92   return data; 93 }; 94 export default { 95  getLunarDate, 96  getLunarDateString, 97 };

用法:spa

import Zodiac from '../js/shengxiao.js';
Zodiac.getLunarDate('1992-1-19');   // 返回值 1991-12-15
Zodiac.getLunarDateString('1991-12-15');  // 返回值
{
day: "十五",
dz: "未",
month: "腊",
tg: "辛",
year: "羊"
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