线程间协做即有多个线程须要按照必定顺序相互协做进行。主要有两种方法来实现,使用锁(互斥)来同步两个任务的行为。另外一种是使用BlockingQueue,它已经帮咱们处理好了同步机制,实现更加简单。git
接下来以一个实际场景为例,进行演示。假设在一个餐馆中有一个服务员,有一个厨师,而服务员要等到厨子把菜作好了才能上菜,而后回来继续等待。而厨师获得新订单后开始作菜。用两种方式实现以前,咱们分析知厨师和服务员分别是一个独立的线程,他们经过餐厅联结在一块儿。在这个模型中厨师表明生产者,服务员表明消费者。Order是他们共享的资源,须要进行同步。github
菜bash
public class Order {
private int num=0;
public Order(int num) {
this.num=num;
}
@Override
public String toString() {
return "order num:"+num;
}
}复制代码
餐馆ide
public class Restaurant {
Order order;
Chef chef=new Chef(this);
Waiter waiter=new Waiter(this);
ExecutorService executorService= Executors.newCachedThreadPool();
public Restaurant() {
order =null;
executorService.execute(chef);
executorService.execute(waiter);
try {
TimeUnit.SECONDS.sleep(5);
}catch (Exception e){
e.printStackTrace();
}
executorService.shutdown();
}
public static void main(String[] args){
new Restaurant();
}
}复制代码
public class Chef implements Runnable {
private Restaurant restaurant;
private int counter=0;
public Chef(Restaurant restaurant) {
this.restaurant = restaurant;
}
@Override
public void run() {
try{
while (!Thread.interrupted()){
synchronized (this){
while (restaurant.meal!=null){
wait();//等服务员上菜,得到新订单
}
}
synchronized (restaurant.waiter){
//得到服务员的锁,让他等我作菜
restaurant.meal=new Meal(counter++);
System.out.print("a meal is done");
Thread.sleep(500);
restaurant.waiter.notifyAll();
//告诉服务员能够上菜了
}
}
}catch (Exception e){
e.printStackTrace();
}
}
}复制代码
服务员ui
public class Waiter implements Runnable {
private Restaurant restaurant;
public Waiter(Restaurant restaurant) {
this.restaurant = restaurant;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
synchronized (this){
while (restaurant.order ==null){
wait();//等待厨师作完菜后被chef的notifyAll()唤醒,注意wait()会释放当前得到的锁
}
}
synchronized (restaurant.chef){
System.out.print("waiter: order up\n");
restaurant.order =null;
restaurant.chef.notifyAll();//告诉厨师能够作菜了
}
}
}catch (Exception e){
e.printStackTrace();
}
}
}复制代码
public class MealQueue extends LinkedBlockingQueue<Order> {
}复制代码
餐馆this
public class Restaurant {
private MealQueue waitQueue;
private MealQueue finishedQueue;
private Chef chef;
private Waiter waiter;
public Restaurant() {
waitQueue = new MealQueue();
finishedQueue = new MealQueue();
chef = new Chef(waitQueue, finishedQueue);
waiter = new Waiter(waitQueue, finishedQueue);
ExecutorService executorService = Executors.newCachedThreadPool();
executorService.execute(chef);
executorService.execute(waiter);
try {
Thread.sleep(5000);
} catch (InterruptedException e) {
e.printStackTrace();
}
executorService.shutdown();
}
public static void main(String[] args){
new Restaurant();
}
}复制代码
厨师spa
public class Chef implements Runnable{
private MealQueue waitQueue;
private MealQueue finishedQueue;
public Chef(MealQueue waitQueue, MealQueue finishedQueue) {
this.waitQueue = waitQueue;
this.finishedQueue = finishedQueue;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
Order order =waitQueue.take();
Thread.sleep(500);
System.out.print("chef:order done "+ order.toString()+"\n");
finishedQueue.add(order);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}复制代码
服务员线程
public class Waiter implements Runnable{
private MealQueue waitQueue;
private MealQueue finishedQueue;
private int count;
public Waiter(MealQueue waitQueue, MealQueue finishedQueue) {
this.waitQueue = waitQueue;
this.finishedQueue = finishedQueue;
count=0;
}
@Override
public void run() {
try {
while (!Thread.interrupted()){
Order newOrder=new Order(count++);
waitQueue.add(newOrder);
System.out.print("waiter:a new order\n");
Order order =finishedQueue.take();
System.out.print("waiter:order complete "+ order.toString()+"\n");
}
} catch (Exception e) {
e.printStackTrace();
}
}
}复制代码
咱们经过两种方法完成了线程的协做,我的以为使用BlockingQueuer更容易也更好管理。最后还有一个例子模拟生产吐司面包,第一步制做吐司,第二步抹黄油,第三步涂果酱。代码已同步到github,再也不赘述。如发现错误,欢迎指正。rest