Python中如何写控制台进度条的整理

进度条和通常的print区别在哪里呢?html

答案就是print会输出一个\n,也就是换行符,这样光标移动到了下一行行首,接着输出,以前已经经过stdout输出的东西依旧保留,并且保证咱们在下面看到最新的输出结果。python

进度条否则,咱们必须再原地输出才能保证他是一个进度条,不然换行了怎么还叫进度条?动画

最简单的办法就是,再输出完毕后,把光标移动到行首,继续在那里输出更长的进度条便可实现,新的更长的进度条把旧的短覆盖,就造成了动画效果。google

能够想到那个转义符了吧,那就是 \r。spa

转义符\r就能够把光标移动到行首而不换行,转义符\n就把光标移动到行首而且换行。code

在python中,输出stdout(标准输出)能够使用sys.stdout.write
例如:htm

#!/usr/bin/env python
# -*- coding=utf-8 -*-
#Using GPL v2
#Author: ihipop@gmail.com
##2010-10-27 22:07
"""
Usage:
Just A Template
"""
from __future__ import division

import sys,time
j = '#'
if __name__ == '__main__':
    for i in range(1,61):
        j += '#'
        sys.stdout.write(str(int((i/60)*100))+'%  ||'+j+'->'+"\r")
        sys.stdout.flush()
        time.sleep(0.5)
print

 

 

第二种思路是用转义符\b
转义符\b是退格键,也就是说把输出的光标往回退格子,这样就能够不用+=了,例如:ip

 

#!/usr/bin/env python
# -*- coding=utf-8 -*-
#Using GPL v2
#Author: ihipop@gmail.com
#2010-10-27 22:07
"""
Usage:
Just A Template
"""
from __future__ import division

import sys,time
if __name__ == '__main__':
    for i in range(1,61):
        sys.stdout.write('#'+'->'+"\b\b")
        sys.stdout.flush()
        time.sleep(0.5)
print

 

 

光标回退2格,写个#再回退,再写,达到增加的目的了utf-8

 

不过写这么多彷佛是废话,在耳边经常听到一句话:那就是不要重复造轮子。实际上python有丰富发lib帮你实现这个东西,你彻底能够把心思放在逻辑开发上而不用注意这些小细节开发

下面要介绍的就是这个类“progressbar”(http://code.google.com/p/python-progressbar/),使用easy_install能够方便的安装这可个类库,其实就一个文件,拿过来放到文件同一个目录下面也直接能够import过来

下面就是基本使用举例:

#!/usr/bin/env python
# -*- coding=utf-8 -*-
#Using GPL v2
#Author: ihipop@gmail.com
#2010-10-27 22:53
"""
Usage:
Just A Template
"""
from __future__ import division

import sys,time
from progressbar import *
total = 1000

#基本用法
progress = ProgressBar()
for i in progress(range(total)):
  time.sleep(0.01)

pbar = ProgressBar().start()
for i in range(1,1000):
    pbar.update(int((i/(total-1))*100))
    time.sleep(0.01)
pbar.finish()

#高级用法
widgets = ['Progress: ', Percentage(), ' ', Bar(marker=RotatingMarker('>-=')),
           ' ', ETA(), ' ', FileTransferSpeed()]
pbar = ProgressBar(widgets=widgets, maxval=10000000).start()
for i in range(1000000):
  # do something
  pbar.update(10*i+1)
  time.sleep(0.0001)
pbar.finish()

 

 

官方示例下载,移步这里:http://code.google.com/p/python-progressbar/source/browse/progressbar/examples.py

再发一个类:

 

#!/usr/bin/env python
# -*- coding=utf-8 -*-
#Using GPL v2
#Author: ihipop@gmail.com
#2010-10-30 13:59
"""
Usage:
Just A Template
"""
class progressbarClass: 
    def __init__(self, finalcount, progresschar=None):
        import sys
        self.finalcount=finalcount
        self.blockcount=0
        #
        # See if caller passed me a character to use on the
        # progress bar (like "*").  If not use the block
        # character that makes it look like a real progress
        # bar.
        #
        if not progresschar: self.block=chr(178)
        else:                self.block=progresschar
        #
        # Get pointer to sys.stdout so I can use the write/flush
        # methods to display the progress bar.
        #
        self.f=sys.stdout
        #
        # If the final count is zero, don't start the progress gauge
        #
        if not self.finalcount : return
        self.f.write('\n------------------- % Progress -------------------\n')
        return

    def progress(self, count):
        #
        # Make sure I don't try to go off the end (e.g. >100%)
        #
        count=min(count, self.finalcount)
        #
        # If finalcount is zero, I'm done
        #
        if self.finalcount:
            percentcomplete=int(round(100*count/self.finalcount))
            if percentcomplete < 1: percentcomplete=1
        else:
            percentcomplete=100
            
        #print "percentcomplete=",percentcomplete
        blockcount=int(percentcomplete/2)
        #print "blockcount=",blockcount
        if blockcount > self.blockcount:
            for i in range(self.blockcount,blockcount):
                self.f.write(self.block)
                self.f.flush()
                
        if percentcomplete == 100: self.f.write("\n")
        self.blockcount=blockcount
        return
    
if __name__ == "__main__":
    from time import sleep
    pb=progressbarClass(8,"*")
    count=0
    while count<9:
        count+=1
        pb.progress(count)
        sleep(0.2)
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