编写shell脚本,计算1-100的和;shell
编写shell脚本,要求输入一个数字,而后计算出从1到输入数字的和,要求,若是输入的数字小于1,则从新输入,直到输入正确的数字为止;bash
编写shell脚本,把/root/目录下的全部目录(只须要一级)拷贝到/tmp/目录下;less
编写shell脚本,批量创建用户user_00, user_01, ... user_100而且全部用户同属于users组;ide
编写shell脚本,截取文件test.log中包含关键词 ‘abc’ 的行中的第一列(假设分隔符为 ”:” ),而后把截取的数字排序(假设第一列为数字),而后打印出重复次数超过10次的列;orm
编写shell脚本,判断输入的IP是否正确(IP的规则是,n1.n2.n3.n4,其中1<n1<255, 0<n2<255, 0<n3<255, 0<n4<255)。 排序
答案:ip
1. #! /bin/bash sum=0 for i in `seq 1 100`; do sum=$[$i+$sum] done echo $sum 2. #! /bin/bash n=0 while [ $n -lt "1" ]; do read -p "Please input a number, it must greater than "1":" n done sum=0 for i in `seq 1 $n`; do sum=$[$i+$sum] done echo $sum 3. #! /bin/bash cd /root for f in `ls `; do if [ -d $f ] ; then cp -r $f /tmp/ fi done 4. #! /bin/bash groupadd users for i in `seq 0 9`; do useradd -g users user_0$i done for j in `seq 10 100`; do useradd -g users user_$j done 5. #! /bin/bash awk -F':' '$0~/abc/ {print $1}' test.log >/tmp/n.txt sort -n n.txt |uniq -c |sort -n >/tmp/n2.txt awk '$1>10 {print $2}' /tmp/n2.txt 6. #! /bin/bash checkip() { if echo $1 |egrep -q '^[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}$' ; then a=`echo $1 | awk -F. '{print $1}'` b=`echo $1 | awk -F. '{print $2}'` c=`echo $1 | awk -F. '{print $3}'` d=`echo $1 | awk -F. '{print $4}'` for n in $a $b $c $d; do if [ $n -ge 255 ] || [ $n -le 0 ]; then echo "the number of the IP should less than 255 and greate than 0" return 2 fi done else echo "The IP you input is something wrong, the format is like 192.168.100.1" return 1 fi } rs=1 while [ $rs -gt 0 ]; do read -p "Please input the ip:" ip checkip $ip rs=`echo $?` done echo "The IP is right!"