leetCode 刷题记录-1. Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

这题是要找出数组中两个数相加的和为target的下标，这道题比较简单可是我也只想到了两重循环来解，复杂度为O（n^2），记录一下防止之后忘记了

public class Solution1 {
    public int[] twoSum(int[] nums, int target) {
        int[] result = new int[2];
        for(int i = 0;i<nums.length-1;i++) {
            for (int j=i+1;j<nums.length;j++) {
                if (nums[i] + nums[j] == target) {
                    result[0] = i;
                    result[1] = j;
                    return result;
                }
            }
        }
        return result;
    }
}