和 Promise.all 相反,当全部的promise被拒绝以后,none方法执行完成的决议,若是存在一个promise执行完成的决议,none方法则执行拒绝javascript
Promise.none = function(promises) { return Promise.all(promises.map(promise => { return new Promise((resolve, reject) => { // Promise.all里边的全部promise实例反过来就行了 return Promise.resolve(promise).then(reject, resolve) }) })) }
const promisesForNoneTest1= [ Promise.reject('1'), Promise.reject('2'), Promise.resolve('3'), Promise.reject('4'), ] Promise.none(promisesForNoneTest1).then(res => { debugger }, res => { debugger // 执行到此 }) const promisesForNoneTest2= [ Promise.reject('1'), Promise.reject('2'), Promise.reject('3'), Promise.reject('4'), ] Promise.none(promisesForNoneTest2).then(res => { debugger // 执行到此 }, res => { debugger })
忽略被拒绝的promise,只须要有一个完成的promise,any方法就执行完成操做,若是所有的promise都被拒绝,any方法执行拒绝操做java
Promise.any = function(promises) { const result = [] return Promise.all(promises.map(promise => { // 控制Promise.all处理的全部的promise都执行reslove决议 return Promise.resolve(promise).then(res => { // 可是只记录实际上决议为resolve的结果值 result.push(res) }, () => { // 防止穿透,这里能够进行拒绝信息的返回 }) })).then(() => { return new Promise((resolve, reject) => { if (result.length > 0) resolve(result) else reject(result) }) }) }
const promisesForAnyTest1= [ Promise.reject('1'), Promise.resolve('2'), Promise.reject('3'), Promise.resolve('4'), Promise.resolve('5'), ] Promise.any(promisesForAnyTest1).then(res => { debugger // 执行到此,res 为 ['2', '4', '5'] }, res => { debugger }) const promisesForAnyTest2= [ Promise.reject('1'), Promise.reject('2'), Promise.reject('3'), Promise.reject('4'), Promise.reject('5'), ] Promise.any(promisesForAnyTest2).then(res => { debugger }, res => { debugger // 执行到此 })
相似race,可是只要有一个promise决议为完成(忽略前边被拒绝的promise),就忽略后边的promisepromise
Promise.first = function(promises) { return new Promise((resolve, reject) => { let rejectNum = 0 promises.forEach(promise => { // 若是当前 promise 决议为reslove,那就直接执行"根promise"的resolve // 不然去记录到拒绝的promise中,而后判断所有的promise拒绝了,执行"根promise"的reject Promise.resolve(promise).then(resolve, () => { if (++rejectNum === promises.length) { // 这里能够控制reject返回的信息 reject() } }) }) }) }
const promisesForFirstTest1= [ Promise.reject('1'), Promise.resolve('2'), Promise.reject('3'), Promise.resolve('4'), ] Promise.first(promisesForFirstTest1).then(res => { debugger // 执行到此,res 为 '2' }, res => { debugger }) const promisesForFirstTest2= [ Promise.reject('1'), Promise.resolve('2'), Promise.reject('3'), Promise.resolve('4'), ] Promise.first(promisesForFirstTest2).then(res => { debugger }, res => { debugger // 执行到此 })
在第二个方法 any 中,用到了Promise.all的方法,里边使用Array.prototype.map方法处理了全部的的promise,当前这个Promise.map方法则但愿把他俩弄到一块儿异步
Promise.map方法但愿实现一个处理批量异步操做的并行迭代方法,本质上是利用Promise.all进行二次封装prototype
Promise.map = function(promises, resolveCallback, rejectCallback) { return Promise.all(promises.map(promise => { return Promise.resolve(promise).then(result => { return resolveCallback(result) }, error => { return Promise.reject(rejectCallback(error)) }) })) }
const promisesForMapTest1= [ Promise.resolve('1'), Promise.resolve('2'), Promise.resolve('3'), Promise.resolve('4'), ] Promise.map(promisesForMapTest1, result => { return result * 100 }, result => { return result }).then(res => { debugger // 执行到此,res为 [100, 200, 300, 400] }, res => { debugger }) const promisesForMapTest2= [ Promise.resolve('1'), Promise.resolve('2'), Promise.reject('3'), Promise.resolve('4'), ] Promise.map(promisesForMapTest2, result => { return result * 100 }, result => { return result }).then(res => { debugger }, res => { debugger // 执行到此,res为 "3" })