【363天】我爱刷题系列122（2018.02.03）

叨叨两句

1. ~

SQL习题017

1

题目描述
获取全部非manager员工当前的薪水状况，给出dept_no、emp_no以及salary ，当前表示to_date='9999-01-01'
CREATE TABLE dept_emp (
emp_no int(11) NOT NULL,
dept_no char(4) NOT NULL,
from_date date NOT NULL,
to_date date NOT NULL,
PRIMARY KEY (emp_no,dept_no));
CREATE TABLE dept_manager (
dept_no char(4) NOT NULL,
emp_no int(11) NOT NULL,
from_date date NOT NULL,
to_date date NOT NULL,
PRIMARY KEY (emp_no,dept_no));
CREATE TABLE employees (
emp_no int(11) NOT NULL,
birth_date date NOT NULL,
first_name varchar(14) NOT NULL,
last_name varchar(16) NOT NULL,
gender char(1) NOT NULL,
hire_date date NOT NULL,
PRIMARY KEY (emp_no));
CREATE TABLE salaries (
emp_no int(11) NOT NULL,
salary int(11) NOT NULL,
from_date date NOT NULL,
to_date date NOT NULL,
PRIMARY KEY (emp_no,from_date));

一、先用INNER JOIN链接employees和salaries，找出当前全部员工的工资状况
二、再用INNER JOIN链接dept_emp表，找到全部员工所在的部门
三、最后用限制条件de.emp_no NOT IN (SELECT emp_no FROM dept_manager WHERE to_date = '9999-01-01')选出当前全部非manager员工，再依次输出dept_no、emp_no、salary

SELECT de.dept_no, s.emp_no, s.salary 
FROM (employees AS e INNER JOIN salaries AS s ON s.emp_no = e.emp_no AND s.to_date = '9999-01-01')
INNER JOIN dept_emp AS de ON e.emp_no = de.emp_no
WHERE de.emp_no NOT IN (SELECT emp_no FROM dept_manager WHERE to_date = '9999-01-01')
此外，还能做以下简化，不链接employees表也能完成：

SELECT de.dept_no, s.emp_no, s.salary 
FROM dept_emp AS de INNER JOIN salaries AS s ON s.emp_no = de.emp_no AND s.to_date = '9999-01-01'
WHERE de.emp_no NOT IN (SELECT emp_no FROM dept_manager WHERE to_date = '9999-01-01')