mysql5.7的3065错误解决方案

有如下sqlmysql

SELECT DISTINCT questionid,questiontype 

FROM x2_questions AS questions,x2_quest2knows AS quest2knows 

WHERE  find_in_set(quest2knows.qkknowsid,:knowsid)  
AND quest2knows.qktype = 0  
AND quest2knows.qkquestionid = questions.questionid  
AND questions.questionstatus = 1  

ORDER BY questionparent asc,questionsequence

运行时提示错误信息linux

Expression #1 of ORDER BY clause is not in SELECT list, references column 'pe6.questions.questionparent' which is not in SELECT list; this is incompatible with DISTINCTsql

错误缘由:安全

mysql5.7版本中,若是DISTINCT和order by一块儿使用将会报3065错误,sql语句没法执行。这是因为5.7版本语法比以前版本语法要求更加严格致使的。ide

解决方案:this

修改mysql的安全模式,即sql_mode。code

步骤:
1.mysql终端中输入下面命令,查看相关配置信息it

show variables like '%sql_mode%';
默认状况下能够看到以下信息
| sql_mode | ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION io

2.设置sql_mode去掉ONLY_FULL_GROUP_BY
推荐在mysql的配置文件my.cnf文件(linux)/my.ini文件(window) 的mysqld中增长或者修改sql_model配置选项class

sql_mode=STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION

3.重启mysql生效
4.验证
在mysql终端中输入下面命令,查看结果。

show variables like '%sql_mode%';

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