建一张表以下:表名为 numbermysql
select * from number where id in ( select distinct n1.id from number n1,number n2,number n3 where (n1.num = n2.num and n2.num = n3.num and ( (n1.id + 1= n2.id and n2.id +1 = n3.id)or (n3.id + 1= n2.id and n2.id +1 = n1.id)or (n3.id + 1= n1.id and n1.id +1 = n2.id) ) ) order by n1.id )
运行结果:sql
思想:将上表中的数据分组取最小。微信
select min(id) as minid,id,num from ((select * from number where id in ( select distinct n1.id from number n1,number n2,number n3 where (n1.num = n2.num and n2.num = n3.num and ( (n1.id + 1= n2.id and n2.id +1 = n3.id)or (n3.id + 1= n2.id and n2.id +1 = n1.id)or (n3.id + 1= n1.id and n1.id +1 = n2.id) ) ) order by n1.id ))as t) group by num ;
运行结果:学习
原表中的数据以下:spa
/* 方法一: 1.建立临时表 2.将须要的数据保存到临时表 3.清空原表,将临时表中的数据保存到原表中 4.删除临时表 */ create temporary table temp select min(id),email from test group by email; truncate table test; insert into test select * from temp; select * from test; drop table temp; /* 方法二: 1.按照邮件分组,把每一组中的最小的id取出放在临时表中 2.删除原表中除临时表中id之外的其余id 对应的数据 */ create temporary table temp select min(id) as minid from test group by email; delete from test where id not in (select minid from temp); drop table temp; /* 方法三: 在原表上操做 */ delete from test where id not in ( select minid from ( select min(id) minid from test group by email )b ); select * from test;
运行结果:3d
建立两张表,表明两个店铺,每一个店铺有不一样的,每一个柜台卖不一样的商品。code
/* 两个商店,每一个店有不一样的柜台,每一个柜台上卖有不一样的商品 */ create table tableA( id int(10) not null primary key auto_increment, monorail varchar(20), variety varchar(50) ); insert into tableA values (1,'a1','苹果'),(2,'a1','梨'),(3,'a3','香蕉'),(4,'a4','苹果'),(5,'a5','西瓜'), (6,'a6','苹果'),(7,'a7','葡萄'),(8,'a8','桃子'); create table tableB( id int(10) not null primary key auto_increment, monorail varchar(20), variety varchar(50) ); insert into tableB values (1,'b1','虾'),(2,'b2','猪肉'),(3,'b3','苹果'),(4,'b4','西瓜'),(5,'b5','梨'), (6,'b6','香蕉');
两个表数据以下:blog
’rem
/* 内链接,查处两个商店共有的商品 */ select * from tablea A INNER JOIN tableb B on A.variety = B.variety ;
运行结果io
/* 左链接,以A表为左表 */ select * from tablea A LEFT JOIN tableb B on A.variety = B.variety ;
运行结果
/* 右链接,以A表为左表 */ select * from tablea A RIGHT JOIN tableb B on A.variety = B.variety ;
运行结果
/* 左外链接,以A表为左表 */ select * from tablea A LEFT JOIN tableb B on A.variety = B.variety Where B.variety is null;
运行结果
/* 右外链接,以A表为左表 */ select * from tablea A RIGHT JOIN tableb B on A.variety = B.variety Where A.variety is null;
运行结果
mysql不支持full (outer) join 故使用union代替
/* 全链接 */ select * from tablea A LEFT JOIN tableb B on A.variety = B.variety ; union select * from tablea A RIGHT JOIN tableb B on A.variety = B.variety ;
运行结果
select * from tablea A LEFT JOIN tableb B on A.variety = B.variety Where B.variety is null union select * from tablea A RIGHT JOIN tableb B on A.variety = B.variety Where A.variety is null
运行结果
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