java并发编程学习之cas-AtomicStampedReference(三)

做用

经过版本号解决ABA的问题。

示例

public class AtomicStampedReferenceDemo {
    static AtomicStampedReference<Integer> stampedReference = new AtomicStampedReference<>(1, 1);

    public static void main(String[] args) throws InterruptedException {
        int oldStamp = stampedReference.getStamp();
        Thread thread1 = new Thread(new Runnable() {
            @Override
            public void run() {
                boolean result = stampedReference.compareAndSet(1, 2, oldStamp, oldStamp + 1);
                System.out.println("当前值：1，预设2,当前版本号：" + stampedReference.getStamp() + ",结果：" + result);
            }
        });
        Thread thread2 = new Thread(new Runnable() {
            @Override
            public void run() {
                try {
                    Thread.sleep(1000);
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
                boolean result = stampedReference.compareAndSet(2, 3, oldStamp, oldStamp + 1);
                System.out.println("当前值：2，预设3,当前版本号：" + stampedReference.getStamp() + ",结果：" + result);
            }
        });
        thread1.start();
        thread2.start();
        Thread.sleep(2000);
        System.out.println("当前值：" + stampedReference.getReference() + ",当前版本号：" + stampedReference.getStamp());
    }
}

运行结果以下：

这里用休眠，让线程1和线程2一次执行，经过结果能够看出来，线程1执行成功，而线程2执行失败。缘由就是由于版本号对不上。