今日内容python
参数app
做用域函数
函数嵌套code
知识点回顾utf-8
函数基本结果作用域
def func(name,age,email): # 函数体(保持缩进一致) a = 123 print(a) return 1111#函数中,出现return后,后面的语句再也不执行。 b = 456 print(b) result = func(1,2,3) # 函数默认返回值:None
参数input
def func(n1,n2): print(n1,n2) func(1,2) func(1,[11,22,3]) func({'k1':'k'},[11,22,3]) # 严格按照顺序传参数:位置方式传参。 # 实际参数能够是任意类型。
返回值it
函数内部执行过程当中遇到return,就终止。
def func1():
return "完成" # 函数每次执行到此,就返回;因此下面代码永远不执行。
for i in range(10):
print(i)
func1()email
def func2(): for i in range(10): print(i) return "完成" print(666) func2()
return 能够返回任意类型
def func():
return (1,2,3)变量
v = func() print(v) # 特殊:返回元组 def func(): return 5,8,"alex" v = func() print(v)
昨日做业题
def func(data_list): val = data_list[1::2] return list(val) v1 = func([1,2,3,4,5,5]) print(v1) v2 = func((1,2,3,4,5,5)) print(v2) # 其余类型能够经过强制转换为列表 # v1 = (1,2,3,4) # v1 = {1,2,3,4} # v1 = {'k1':'v1','k2':'v2'} v1 = "asdfasdfasdf" v2 = list(v1) print(v2) def func(arg): if len(arg) > 5: return True else: return False data = func([1111,22,3,42,12]) data = func((1111,22,3,42,12) def func(a1,a2): if a1 > a2: return a1 else: return a2 v1 = func(1,2) v2 = func(11,2) def func(a1,a2): return a1 if a1 > a2 else a2 v1 = func(1,2) v2 = func(11,2) def func(name,gender,age,edu): # template = "%s*%s*%s*%s" %(name,gender,age,edu,) # return template data_list = [name,gender,age,edu] return "*".join(data_list) n1 = input('>') n2 = input('>') n3 = input('>') n4 = input('>') result = func(n1,n2,n3,n4) print(result) def func(max_range): result = [1,1] while True: val = result[-1] + result[-2] if val > max_range: break result.append(val) return result v = func(100) print(v) def func(name): with open('data.txt',mode='r',encoding='utf-8') as obj: # 方式一 content = obj.read() flag = False row_list = content.split('\n') # ['1|alex|123123','2|eric|rwerwe','3|wupeiqi|pppp'] for row in row_list: v= row.split('|') if v[1] == name: flag = True break return flag func('alex') func('eric') # ############################################ def func(name): with open('data.txt',mode='r',encoding='utf-8') as obj: # 方式一 content = obj.read() row_list = content.split('\n') # ['1|alex|123123','2|eric|rwerwe','3|wupeiqi|pppp'] for row in row_list: v= row.split('|') if v[1] == name: return True v1 = func('alex') if v1: print('存在') else: print('不存在')
今日内容详细
参数
任意类型
def func(a1,a2,a3):
print(a1,a2,a3)
位置传参(调用函数并传入参数)【执行】
def func(a1,a2):
print(a1,a2)
func(1,3)
关键字传参【执行】
def func(a1, a2):
print(a1, a2)
func(a2=99,a1=2) # 关键字传参数和位置传参能够混合使用(位置传入的参数 > 关键字参数在后 = 总参数个数) def func1(a1, a2, a3): print(a1, a2, a3) # func(1, 2, a3=9) # func(1, a2=2, a3=9) # func(a1=1, a2=2, a3=9) # func(a1=1, 2,3) # 错误
默认参数【定义】
def func(a1,a2,a3=9,a4=10):
print(a1,a2,a3,a4)
func(11,22) func(11,22,10) func(11,22,10,100) func(11,22,10,a4=100) func(11,22,a3=10,a4=100) func(11,a2=22,a3=10,a4=100) func(a1=11,a2=22,a3=10,a4=100)
调用函数无
def func(args):
print(args)
func(1,2,3,4) (1, 2, 3, 4)
调用函数有
def func(args):
print(args)
func(*(1,2,3,4)) func(*[1,2,3,4]) (1, 2, 3, 4) (1, 2, 3, 4)
只能用位置传参
def func(*args):
print(args)
# func(1) # func(1,2) func(1,2) # args=(1, 2) func((11,22,33,44,55)) # args=((11,22,33,44,55),),不带星号,至关于把当当成一个总体,看成元组的一个元素。 func(*(11,22,33,44,55)) # args=(11,22,33,44,55) (1,) (1, 2) (1, 2) ((11, 22, 33, 44, 55),) (11, 22, 33, 44, 55)
调用函数无
def func(kwargs):
print(kwargs)
func(k1=1,k2="alex") {'k1': 1, 'k2': 'alex'}
综合应用:无敌 + 无敌 => 真无敌
def func(*args,**kwargs):
print(args,kwargs)
# func(1,2,3,4,5,k1=2,k5=9,k19=999) func(*[1,2,3],k1=2,k5=9,k19=999) func(*[1,2,3],**{'k1':1,'k2':3}) func(111,222,*[1,2,3],k11='alex',**{'k1':1,'k2':3}) (1, 2, 3, 4, 5) {'k1': 2, 'k5': 9, 'k19': 999} (1, 2, 3) {'k1': 2, 'k5': 9, 'k19': 999} (1, 2, 3) {'k1': 1, 'k2': 3} (111, 222, 1, 2, 3) {'k11': 'alex', 'k1': 1, 'k2': 3}参数相关重点:
定义函数
def func1(a1,a2):
pass
def func2(a1,a2=None):
pass
def func3(*args,**kwargs):
pass
调用函数
位置参数 > 关键字参数
做用域
python中:
函数:局部做用域
a = 1
def s1():
x1 = 666
print(x1)
print(a)
print(b)
b = 2 print(a) s1() a = 88888 def s2(): print(a,b) s1() s2() ====== 1 666 1 2 88888 2 666 88888 2
做用域中查找数据规则:优先在本身的做用域找数据,本身没有就去 "父级" -> "父级" -> 直到全局,所有么有就报错。注意:父级做用域中的值究竟是什么?
x = 10
def func():
x = 9
print(x)
func()
练习题:
#!/usr/bin/env python
# -- coding:utf-8 --
# x = 10 # def func(): # x = 9 # print(x) # def x1(): # x = 999 # print(x) # # func() # x = 10 # def func(): # x = 9 # print(x) # def x1(): # x = 999 # print(x) # x1() # # func() # x = 10 # def func(): # x = 9 # print(x) # def x1(): # x = 999 # print(x) # print(x) # x1() # # func() # x = 10 # def func(): # x = 8 # print(x) # def x1(): # x = 999 # print(x) # x1() # print(x) # # func() # x = 10 # def func(): # x = 8 # print(x) # def x1(): # print(x) # x1() # print(x) # # func() # x = 10 # def func(): # x = 8 # print(x) # def x1(): # print(x) # x = 9 # x1() # x = 10 # print(x) # # func() # # x = 10 # def func(): # x = 8 # print(x) # def x1(): # print(x) # # x1() # x = 9 # x1() # x = 10 # print(x) # # func()
子做用域中只能 找到父级中的值 ,默认没法从新为父级的变量进行赋值。(global/nonlocal能够强制作)
# #####################
name = 'oldboy'
def func():
name = 'alex' # 在本身做用域再建立一个这样的值。
print(name)
func()
print(name)
# ##################### name = [1,2,43] def func(): name.append(999)#列表为可变类型,能够修改。这里是修改,不是从新赋值。 print(name) func() print(name) # ###################### 若是非要对全局的变量进行赋值 # 示例一 name = ["老男孩",'alex'] def func(): global name name = '我' func() print(name) # 示例一 name = "老男孩" def func(): name = 'alex' def inner(): global name name = 999 inner() print(name) func() print(name) name = "老男孩" def func(): name = 'alex' def inner(): global name name = 999 inner() print(name) func() print(name) # ############################## nonlocal name = "老男孩" def func(): name = 'alex' def inner(): nonlocal name # 找到上一级的name name = 999 inner() print(name) func() print(name)
总结
补充
所有变量之后必须所有是大写
USER_LIST = [11,22,3]
def func(): name = 'asdf' USER_LIST.append(12) USER_LIST.append(name) func() print(USER_LIST)