Educational Codeforces Round 52: E. Side Transmutations（burnside引理）
E. Side Transmutations 题意： 给一个字符集A，考虑所有长度为n的字符串S，里面所有的字符都来自于字符集A，再给出m个参数b[1]~b[m]，定义一种改变字符串S的操作为按顺序执行如下内容： 从b[]里选一个当k 把S的前k个字符和后k个字符分别倒置，然后交换位置 定义两个字符串等价，当且仅当一个字符串能经过若干次上述操作后变成另一个字符串 统计有多少个本质不同的字符
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相关文章
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