ValueError: Input 0 is incompatible with layer sequential: expected shape=(None, None, 1), found...
【python报错】 ValueError: Input 0 is incompatible with layer sequential: expected shape=(None, None, 1), found shape=[None, 1, 3] 报错代码： look_back=3 model.add(LSTM(32,input_shape=(look_back,1),return_sequ
相关文章
- 1. ValueError:Input 0 is incompatible with layer lstm_1: expected ndim=3,found ndim=2
- 2. ValueError: Input 0 of node ... was passed float from ... incompatible with expected float_ref.
- 3. 解决ValueError: Shape must be rank 1 but is rank 0 for ‘bn_conv1/Reshape_4’ (op: ‘Reshape’) with input
- 4. tensorflow "ValueError: None values not supported."
- 5. `if not x:` 和`if x is not None:`和`if not x is None:`
- 6. none
- 7. Select n numbers from 1 to m with all of array 'all' and none of array 'none'
- 8. keras报错：ValueError: `steps_per_epoch=None` is only valid for a generator based on the `keras.utils.S
- 9. Exclusions: ----------- None Unconditional classes:
- 10. None
- 更多相关文章...
- • XSLT
- • Docker 安装 Python - Docker教程
- • Kotlin学习（一）基本语法
- • Docker容器实战(七) - 容器眼光下的文件系统
相关标签/搜索
每日一句
-
每一个你不满意的现在，都有一个你没有努力的曾经。
欢迎关注本站公众号,获取更多信息
相关文章
- 1. ValueError:Input 0 is incompatible with layer lstm_1: expected ndim=3,found ndim=2
- 2. ValueError: Input 0 of node ... was passed float from ... incompatible with expected float_ref.
- 3. 解决ValueError: Shape must be rank 1 but is rank 0 for ‘bn_conv1/Reshape_4’ (op: ‘Reshape’) with input
- 4. tensorflow "ValueError: None values not supported."
- 5. `if not x:` 和`if x is not None:`和`if not x is None:`
- 6. none
- 7. Select n numbers from 1 to m with all of array 'all' and none of array 'none'
- 8. keras报错：ValueError: `steps_per_epoch=None` is only valid for a generator based on the `keras.utils.S
- 9. Exclusions: ----------- None Unconditional classes:
- 10. None