1、线程如何中止安全
使用stop()不安全。它会解除由线程获取的全部锁定,并且若是对象处于一种不连贯状态,那么其余线程能在那种状态下检查和修改它们。结果很难检查出真正的问题所在。suspend()方法容易发生死锁。调用suspend()的时候,目标线程会停下来,但却仍然持有在这以前得到的锁定。此时其余任何线程都不能访问锁定的资源,除非被"挂起"的线程恢复运行。对任何线程来讲,若是它们想恢复目标线程,同时又试图使用任何一个锁定的资源,就会形成死锁。因此不该该使用suspend()。正确的作法是而应在本身的Thread类中置入一个标志,指出线程应该活动仍是挂起。若标志指出线程应该挂起,便用wait()命其进入等待状态。若标志指出线程应当恢复,则用一个notify()从新启动线程。jdk1.5后提供了condition对象,这个对象的await()和singal()方法也能够达到线程通讯的效果。ide
2、wait和notify实例oop
子线程循环10次,主线程循环100次。接着子线程循环10次,主线程循环100次。如此循环50次。摘自张孝祥老师线程视频源码。this
public class TraditionalThreadCommunicationspa
{线程
public static void main(String[] args)视频
{对象
final Business business = new Business();资源
new Thread(new Runnable() {源码
public void run()
{
for (int i = 1; i <= 50; i++)
{
business.sub(i);
}
}
}).start();
for (int i = 1; i <= 50; i++)
{
business.main(i);
}
}
}
class Business
{
private boolean bShouldSub = true;
public synchronized void sub(int i)
{
while (!bShouldSub)
{
try
{
this.wait();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 10; j++)
{
System.out.println("sub thread sequence of " + j + ",loop of " + i);
}
bShouldSub = false;
this.notify();
}
public synchronized void main(int i)
{
while (bShouldSub)
{
try
{
this.wait();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 100; j++)
{
System.out.println("main thread sequence of " + j + ",loop of " + i);
}
bShouldSub = true;
this.notify();
}
}
3、Condition实例
public class Condition1Test
{
public static void main(String[] args)
{
final BusinessLock business = new BusinessLock();
new Thread(new Runnable() {
public void run()
{
for (int i = 1; i <= 50; i++)
{
business.sub(i);
}
}
}).start();
for (int i = 1; i <= 50; i++)
{
business.main(i);
}
}
}
class BusinessLock
{
private boolean bShouldSub = true;
ReentrantLock lock = new ReentrantLock();
Condition condition = lock.newCondition();
public void sub(int i)
{
lock.lock();
try
{
while (!bShouldSub)
{
try
{
condition.await();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 10; j++)
{
System.out.println("sub thread sequence of " + j + ",loop of " + i);
}
bShouldSub = false;
condition.signal();
}
finally
{
lock.unlock();
}
}
public void main(int i)
{
lock.lock();
try
{
while (bShouldSub)
{
try
{
condition.await();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 100; j++)
{
System.out.println("main thread sequence of " + j + ",loop of " + i);
}
bShouldSub = true;
condition.signal();
}
finally
{
lock.unlock();
}
}
}
4、Condition实例扩展
三个线程相互通讯,main循环100次,sub2循环10次,sub3循环10次。接着main循环100次,sub2循环10次,sub3循环10次。如此循环50次。
public class Condition2Test
{
public static void main(String[] args)
{
final BusinessLock2 business = new BusinessLock2();
new Thread(new Runnable() {
public void run()
{
for (int i = 1; i <= 50; i++)
{
business.main(i);
}
}
}).start();
new Thread(new Runnable() {
public void run()
{
for (int i = 1; i <= 50; i++)
{
business.sub2(i);
}
}
}).start();
new Thread(new Runnable() {
public void run()
{
for (int i = 1; i <= 50; i++)
{
business.sub3(i);
}
}
}).start();
}
}
class BusinessLock2
{
private int bShouldSub = 1;
ReentrantLock lock = new ReentrantLock();
Condition condition1 = lock.newCondition();
Condition condition2 = lock.newCondition();
Condition condition3 = lock.newCondition();
public void main(int i)
{
lock.lock();
try
{
while (bShouldSub != 1)
{
try
{
condition1.await();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 100; j++)
{
System.out.println("main thread sequence of " + j + ",loop of " + i);
}
bShouldSub = 2;
condition2.signal();
}
finally
{
lock.unlock();
}
}
public void sub2(int i)
{
lock.lock();
try
{
while (bShouldSub != 2)
{
try
{
condition2.await();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 10; j++)
{
System.out.println("sub2 thread sequence of " + j + ",loop of " + i);
}
bShouldSub = 3;
condition3.signal();
}
finally
{
lock.unlock();
}
}
public void sub3(int i)
{
lock.lock();
try
{
while (bShouldSub != 3)
{
try
{
condition3.await();
}
catch (InterruptedException e)
{
e.printStackTrace();
}
}
for (int j = 1; j <= 10; j++)
{
System.out.println("sub3 thread sequence of " + j + ",loop of " + i);
}
bShouldSub = 1;
condition1.signal();
}
finally
{
lock.unlock();
}
}
}