equals与hashcode间的关系是这样的:bash
一、若是两个对象相同(即用equals比较返回true),那么它们的hashCode值必定要相同;ide
二、若是两个对象的hashCode相同,它们并不必定相同(即用equals比较返回false)。ui
为何必需要重写hashcode方法,其实简单的说就是为了保证同一个对象,保证在equals相同的状况下hashcode值一定相同,若是重写了equals而未重写hashcode方法,可能就会出现两个没有关系的对象equals相同的(由于equals都是根据对象的特征进行重写的),但hashcode确实不相同的。this
@Data
public class ShopProductSpecValueDTO {
private String id;
private String productId;
private String specId;
private String specvalueId;
private String createdBy;
private Date dateCreated;
private String updatedBy;
private Date dateUpdated;
public ShopProductSpecValueDTO(){
}
public ShopProductSpecValueDTO(String productId,String specId,String specvalueId){
this.productId = productId;
this.specId = specId;
this.specvalueId=specvalueId;
}
@Override
public int hashCode() {
int result = id != null ? id.hashCode() : 0;
result = 31 * result + (productId != null ? productId.hashCode() : 0);
result = 31 * result + (specId != null ? specId.hashCode() : 0);
result = 31 * result + (specvalueId != null ? specvalueId.hashCode() : 0);
return result;
}
@Override
public boolean equals(Object obj) {
if (obj == null){
return false;
}
if (this == obj){
return true;
}
if (getClass() != obj.getClass()){
return false;
}
ShopProductSpecValueDTO o = (ShopProductSpecValueDTO) obj;
if (this.productId != null ? !this.productId.equals(o.productId) : o.productId != null) return false;
if (this.specId != null ? !this.specId.equals(o.specId) : o.specId != null) return false;
if (this.specvalueId != null ? !this.specvalueId.equals(o.specvalueId) : o.specvalueId != null) return false;
return true;
}
}
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