线上最近出现了批量insert
的死锁,百思不得姐。死锁记录以下html
2018-10-26T11:04:41.759589Z 8530809 [Note] InnoDB:
*** (1) TRANSACTION:
TRANSACTION 1202026765, ACTIVE 0 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 3 lock struct(s), heap size 1136, 3 row lock(s), undo log entries 1
MySQL thread id 8532863, OS thread handle 139858337453824, query id 16231472122 10.111.10.143 seewo update
INSERT IGNORE INTO xx_performance_type_label_relation(label_id, performance_type_id, type, create_time)
VALUES
('bb0394e670644168a998a93a3ed521bc', '06b96ee0bab84d71bb17bf9645d3aa54', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '27d82e2331b241e1a9c9c0a74ec21099', -1, now())
,
('bb0394e670644168a998a93a3ed521bc', '3100b5978fb24f56b327d25732a7d7a7', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '435a1e19ce6e4e5bbb84240b3b34cf03', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '447fe27199ca40e289ef2834469d9a78', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '87a52c4d00844b5bb9eb75e8fe34202a', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', 'c6a0e26983bd4fae837d5ee2f4efeef8', 1, now())
2018-10-26T11:04:41.759635Z 8530809 [Note] InnoDB: *** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 505 page no 9912 n bits 288 index uk_performance_type_id_label_id of table `masaike`.`xx_performance_type_label_relation` trx id 1202026765 lock_mode X locks gap before rec insert intention waiting
2018-10-26T11:04:41.759674Z 8530809 [Note] InnoDB: *** (2) TRANSACTION:
TRANSACTION 1202026764, ACTIVE 0 sec inserting
mysql tables in use 1, locked 1
3 lock struct(s), heap size 1136, 3 row lock(s), undo log entries 1
MySQL thread id 8530809, OS thread handle 139858469242624, query id 16231472119 10.111.10.153 seewo update
INSERT IGNORE INTO xx_performance_type_label_relation(label_id, performance_type_id, type, create_time)
VALUES
('bb0394e670644168a998a93a3ed521bc', '06b96ee0bab84d71bb17bf9645d3aa54', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '27d82e2331b241e1a9c9c0a74ec21099', -1, now())
,
('bb0394e670644168a998a93a3ed521bc', '3100b5978fb24f56b327d25732a7d7a7', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '435a1e19ce6e4e5bbb84240b3b34cf03', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '447fe27199ca40e289ef2834469d9a78', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', '87a52c4d00844b5bb9eb75e8fe34202a', 1, now())
,
('bb0394e670644168a998a93a3ed521bc', 'c6a0e26983bd4fae837d5ee2f4efeef8', 1, now())
2018-10-26T11:04:41.759713Z 8530809 [Note] InnoDB: *** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 505 page no 9912 n bits 288 index uk_performance_type_id_label_id of table `masaike`.`xx_performance_type_label_relation` trx id 1202026764 lock mode S
2018-10-26T11:04:41.759753Z 8530809 [Note] InnoDB: *** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 505 page no 9912 n bits 288 index uk_performance_type_id_label_id of table `masaike`.`xx_performance_type_label_relation` trx id 1202026764 lock_mode X locks gap before rec insert intention waiting
2018-10-26T11:04:41.759784Z 8530809 [Note] InnoDB: *** WE ROLL BACK TRANSACTION (2)
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第一反应是批量insert,insert的顺序不同致使的死锁。可是这个在这里是不成立的。缘由有两点java
如今采用一个简化的表,作实验mysql
CREATE TABLE `t1` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`a` varchar(5) NOT NULL DEFAULT '',
`b` varchar(5) NOT NULL DEFAULT '',
PRIMARY KEY (`id`),
UNIQUE KEY `uk_name` (`a`,`b`)
) ENGINE=InnoDB;
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在记录不存在的状况下,两个一样顺序的批量insert同时执行,第二个会进行锁等待状态sql
首先truncate t1;
bash
t1 | t2 | |
---|---|---|
begin; | begin; | |
insert ignore into t1(a, b)values("1", "1"); | 成功 | |
insert ignore into t1(a, b)values("1", "1"); | 锁等待状态 |
能够看到目前锁的状态ui
mysql> select * from information_schema.innodb_locks;
+-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+
| lock_id | lock_trx_id | lock_mode | lock_type | lock_table | lock_index | lock_space | lock_page | lock_rec | lock_data |
+-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+
| 31AE:54:4:2 | 31AE | S | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' |
| 31AD:54:4:2 | 31AD | X | RECORD | `d1`.`t1` | `uk_name` | 54 | 4 | 2 | '1', '1' |
+-------------+-------------+-----------+-----------+------------+------------+------------+-----------+----------+-----------+
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在咱们执行事务t1
的insert时,没有在任何锁的断点处出现,这跟MySQL插入的原理有关系spa
insert 加的是隐式锁。什么是隐式锁?隐式锁的意思就是没有锁
线程
在t1插入记录时,是不加锁的。这个时候事务t1还未提交的状况下,事务t2尝试插入的时候,发现有这条记录,t2尝试获取S锁,会断定记录上的事务id是否活跃,若是活跃的话,说明事务未结束,会帮t1把它的隐式锁提高为显式锁(X锁)debug
源码以下 日志
t2获取S
锁的结果:DB_LOCK_WAIT
批量插入顺序不一致的致使的死锁日志不是等待插入意向锁
t1 | t2 | |
---|---|---|
begin | ||
insert into t1(a, b)values("1", "1"); | 成功 | |
insert into t1(a, b)values("2", "2"); | 成功 | |
insert into t1(a, b)values("2", "2"); | t1尝试获取S锁,把t2的隐式锁提高为显式X锁,进入DB_LOCK_WAIT | |
insert into t1(a, b)values("1", "1"); | t2尝试获取S锁,把t1的隐式锁提高为显式X锁,产生死锁 |
------------------------
LATEST DETECTED DEADLOCK
------------------------
181101 9:48:36
*** (1) TRANSACTION:
TRANSACTION 3309, ACTIVE 215 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2
MySQL thread id 2, OS thread handle 0x70000a845000, query id 58 localhost root update
insert into t1(a, b)values("2", "2")
*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 3309 lock mode S waiting
Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 1; hex 32; asc 2;;
1: len 1; hex 32; asc 2;;
2: len 4; hex 80000002; asc ;;
*** (2) TRANSACTION:
TRANSACTION 330A, ACTIVE 163 sec inserting
mysql tables in use 1, locked 1
3 lock struct(s), heap size 376, 2 row lock(s), undo log entries 2
MySQL thread id 3, OS thread handle 0x70000a888000, query id 59 localhost root update
insert into t1(a, b)values("1", "1")
*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock_mode X locks rec but not gap
Record lock, heap no 3 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 1; hex 32; asc 2;;
1: len 1; hex 32; asc 2;;
2: len 4; hex 80000002; asc ;;
*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 55 page no 4 n bits 72 index `uk_name` of table `d1`.`t1` trx id 330A lock mode S waiting
Record lock, heap no 2 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 1; hex 31; asc 1;;
1: len 1; hex 31; asc 1;;
2: len 4; hex 80000001; asc ;;
*** WE ROLL BACK TRANSACTION (2)
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到目前为止,已经陷入了僵局,彻底无法复现死锁的状况。看了代码,发如今insert以前有一个delete,可是delete与insert不在一个事务里面,也就是delete提交之后,才进行批量insert,真正出问题的地方在批量insert的地方。一开始就排除了delete对后面的影响,难道不在一个事务,也会有影响?
写了一个代码去模拟,有很大几率会复现
fun test() {
dao.delete() // 对应delete from
// sleep for 10ms
dao.insert() // 对应insert ignore
}
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对应的 SQL 以下,注意是两个事务
begin;
delete from t1 where a = '25'
commit;
begin;
INSERT ignore INTO `t1` (`a`, `b`) VALUES('25','1')
commit;
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这个代码在两个线程同时调用的时候,很是容易死锁。
后来翻遍了网上相关的死锁案例,有一个关于purge删除的过程可能跟这个有关系。
若是标记为删除,说明事务已经提交,还没来得及 purge,这时后面的事务加
S
锁等待;
在源码中打印一些日志。 1.在storage/innobase/row/row0ins.c
的row_ins_set_shared_rec_lock
增长日志,能够看到对惟一索引增长S
锁的过程
if (dict_index_is_clust(index)) {
err = lock_clust_rec_read_check_and_lock(
0, block, rec, index, offsets, LOCK_S, type, thr);
} else {
err = lock_sec_rec_read_check_and_lock(
0, block, rec, index, offsets, LOCK_S, type, thr);
// 增长以下日志
fprintf(stderr, "row_ins_set_shared_rec_lock %s %lu %d\n" , index->name, type, err);
}
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2.在lock_rec_enqueue_waiting
增长日志,能够看到锁等待的状况
static
enum db_err
lock_rec_enqueue_waiting(
{
fprintf(stderr, "lock_rec_enqueue_waiting::::: %s %lu\n" , index->name, type_mode);
}
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日志大概以下
row_ins_set_shared_rec_lock uk_name 0 9 (t1获取S锁成功)
row_ins_set_shared_rec_lock uk_name 0 9 (t2获取S锁成功)
lock_rec_enqueue_waiting::::: uk_name 2563(t1 X锁进如锁等待)
lock_rec_enqueue_waiting::::: uk_name 2563(t2 X锁进如锁等待)
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其中2563=2048+512+3=LOCK_INSERT_INTENTION+LOCK_GAP+LOCK_X
这个过程跟很是经典的三个事务同时insert,一个回滚,剩下的两个事务一个成功,一个死锁,实际上是如出一辙的原理。
三个 insert ignore,一个回滚形成的死锁
insert语句都是insert ignore into t1(a, b)values("1", "1");
如下省略
t1 | t2 | t3 | 备注 |
---|---|---|---|
begin | begin | begin | |
insert | 成功 | ||
insert | 把t1的隐式锁提高为X锁,t2进入进入S锁等待 | ||
insert | t3进入进入S锁等待 | ||
rollback; | t1回滚之后,释放X锁,t2和t3同时拿到了S锁 | ||
ok | deadlock | t2和t3都想拿插入意向锁X锁,形成死锁条件 |
死锁日志,跟咱们案例中的如出一辙
------------------------
LATEST DETECTED DEADLOCK
------------------------
181101 23:22:59
*** (1) TRANSACTION:
TRANSACTION 5032, ACTIVE 11 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 4 lock struct(s), heap size 1248, 2 row lock(s), undo log entries 1
MySQL thread id 5, OS thread handle 0x70000d736000, query id 125 localhost root update
insert ignore into t1(a, b)values("1", "1")
*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 56 page no 4 n bits 584 index `uk_name` of table `d1`.`t1` trx id 5032 lock_mode X locks gap before rec insert intention waiting
Record lock, heap no 139 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 3; hex 313031; asc 101;;
1: len 3; hex 313031; asc 101;;
2: len 4; hex 800007b1; asc ;;
*** (2) TRANSACTION:
TRANSACTION 5033, ACTIVE 6 sec inserting
mysql tables in use 1, locked 1
4 lock struct(s), heap size 1248, 2 row lock(s), undo log entries 1
MySQL thread id 6, OS thread handle 0x70000d779000, query id 126 localhost root update
insert ignore into t1(a, b)values("1", "1")
*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 56 page no 4 n bits 584 index `uk_name` of table `d1`.`t1` trx id 5033 lock mode S locks gap before rec
Record lock, heap no 139 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 3; hex 313031; asc 101;;
1: len 3; hex 313031; asc 101;;
2: len 4; hex 800007b1; asc ;;
*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 56 page no 4 n bits 584 index `uk_name` of table `d1`.`t1` trx id 5033 lock_mode X locks gap before rec insert intention waiting
Record lock, heap no 139 PHYSICAL RECORD: n_fields 3; compact format; info bits 0
0: len 3; hex 313031; asc 101;;
1: len 3; hex 313031; asc 101;;
2: len 4; hex 800007b1; asc ;;
*** WE ROLL BACK TRANSACTION (2)
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目前来看,获得的结论是:
一个已提交可是未purge掉的记录会形成后续插入获取S共享锁,两个事务同时获取S锁,而后尝试获取插入意向锁,形成死锁
网上大神梳理的insert流程
首先对插入的间隙加插入意向锁(Insert Intension Locks)
而后判断插入记录是否有惟一键,若是有,则进行惟一性约束检查
插入记录并对记录加 X 记录锁;
上面是我 debug 源码获得的一些结论,若是个人理解有误的话,记得留言告诉我
如下为参考文档