Python——时间换算

利用datetime模块进行不一样时间单位的换算java

from datetime import timedelta

a = timedelta(days=2, hours=6)
b = timedelta(hours=4.5)
c = a + b
print(c.days)
print(c.seconds)
print(c.seconds / 3600)

 表示特定的日期和时间python

from datetime import datetime
a = datetime(2016, 8, 30)
print(a + timedelta(days=10))
b = datetime(2016, 9, 30)
d = b - a
print(d.days)

now = datetime.today()
print(now)
print(now + timedelta(minutes=10))

 datetime模块能够正确处理闰年code

a = datetime(2012, 3, 1)
b = datetime(2012, 2, 28)
print((a-b).days)
c = datetime(2013, 3, 1)
d = datetime(2013, 2, 28)
print((c-d).days)

 处理更为复杂的日期问题,如处理时区,模糊时间范围,计算节日的日期等能够用dateutil模块blog