[Swift]遍历字符串

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Swift中没法再使用传统形式的for循环。git

1 //传统for循环形式不适用于Swift
2 for(单次表达式;条件表达式;末尾循环体){中间循环体;}

字符串遍历方法1:使用该indices属性能够访问字符串中各个字符的全部索引。github

1 let str = "Strengthen!"
2 for index in str.indices { 3     print("\(str[index]) ", terminator: "") 4 } 5 // Prints "S t r e n g t h e n ! "

字符串遍历方法2:每一个String值都有一个关联的索引类型,String.Index它对应Character于字符串中每一个值的位置。要访问远离给定索引的索引,能够使用该index(_:offsetBy:)方法而不是屡次调用其中一种方法。您能够使用下标语法来访问Character特定String索引。数组

 1 extension String {  2     //subscript函数能够检索数组中的值  3     //按照索引方式读取字符
 4     subscript (_ i: Int) -> Character {  5         //读取字符
 6         get {return self[index(startIndex, offsetBy: i)]}  7  }  8 }  9 
10 //方式1
11 let str = "Strengthen!"
12 for num in 0..<str.count 13 { 14     let char:Character = str[str.index(str.startIndex,offsetBy: num)] 15      print("\(char) ", terminator: "") 16 } 17 //Prints "S t r e n g t h e n ! " 18 
19 //方式2
20 for num in 0..<str.count 21 { 22     let char:Character = str[num] 23      print("\(char) ", terminator: "") 24 } 25 //Prints "S t r e n g t h e n ! "

字符串遍历方法3:遍历字符串的每个字符微信

1 let str = "Strengthen!"
2 for char in str.characters { 3     print("\(char) ", terminator: "") 4 } 5 //Prints "S t r e n g t h e n ! "

字符串遍历方法4:遍历字符串的每个字符对应ASCII的整数值ide

1 let str = "Strengthen"
2 var strUnicodeScalars = Array(str.utf8) 3 print(strUnicodeScalars) 4 //Prints [83, 116, 114, 101, 110, 103, 116, 104, 101, 110]
5 for charNum in strUnicodeScalars 6 { 7     print("\(charNum) ", terminator: "") 8 } 9 //Prints "83 116 114 101 110 103 116 104 101 110"

倒序遍历字符串方法1:reversed()函数

1 let str = "Strengthen!"
2 for char in str.reversed() { 3     print("\(char) ", terminator: "") 4 } 5 //Prints ! n e h t g n e r t S 

倒序遍历字符串方法2stride函数 -返回一个任意可变步长类型值的序列。可变步长类型是能够设置偏移量的一维标量。学习

 1 let str = "Strengthen!"
 2 //from,to,by 最后一个值是 >(或<) to的值
 3 for num in stride(from: str.count-1,to: 0,by: -1)  4 {  5     let char:Character = str[str.index(str.startIndex,offsetBy: num)]  6      print("\(char) ", terminator: "")  7 }  8 //Prints "! n e h t g n e r t"  9 
10 //from,through,by 最后一个值是 >=(或<=) through的值
11 for num in stride(from: str.count-1,through: 0,by: -1) 12 { 13     let char:Character = str[str.index(str.startIndex,offsetBy: num)] 14      print("\(char) ", terminator: "") 15 } 16 //Prints "! n e h t g n e r t S "

字符串转字符数组:编码

1 let str = "I am Strengthen"
2 let array = str.components(separatedBy:" ") 3 print("\(array) ", terminator: "") 4 //["I", "am", "Strengthen"] 

字符数组转字符串:url

 1 /*字符数组转字符串*/
 2 let arrayStr = ["s","t","r","e","n","g","t","h","e","n","!"]  3 
 4 //方式1
 5 let str1 = arrayStr.joined(separator: "")  6 let str2 = arrayStr.joined(separator: "-")  7 print("\(str1) ", terminator: "")  8 print("\(str2) ", terminator: "")  9 //strengthen! 10 //s-t-r-e-n-g-t-h-e-n-! 11 
12 //方式2:注意与方式1比较,方式2只在首位添加"-"
13 let str3 = arrayStr.reduce("", {$0 + $1}) 14 let str4 = arrayStr.reduce("-", {$0 + $1}) 15 print("\(str3) ", terminator: "") 16 print("\(str4) ", terminator: "") 17 //strengthen! 18 //-strengthen! 
19 
20 /*整数数组转字符串*/
21 let arrayInt = [0,1,2,3,4,5,6,7,8,9] 22 let dataInt = arrayInt.map(String.init) 23 let strInt = dataInt.joined(separator: "-") 24 print("\(strInt) ", terminator: "") 25 //0-1-2-3-4-5-6-7-8-9

最强字符串解析,你想知道,我都有!!!

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[Swift]字符串根据索引获取指定字符,依据ASCII编码,实现字符和整数的快速转换

[Swift]字符串(String类、NSString类)经常使用操做

[Swift]扩展String类:extension String

[Swift]ASCII值的获取和转换:extension Character类和extension Int

[Swift]字符串大小写转换,同时实现本地化或设置语言环境

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