选靓号 拼多多[编程题](python 95%解)

95%经过率python l1 = input().split(' ') original_str = input() strl2 = list(original_str) l2 = [int(val) for val in strl2] n,k = int(l1[0]),int(l1[1]) #一共n位 #须要有k个相同 all_val = [] diff = 0 for each in l2:

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