Rebuild+三分

  https://blog.csdn.net/LuRiCheng/article/details/70135430 当n%2==1 假如n=3 r1+r2=L1 r2+r3=L2 r3+r1=L3 L1-L2+L3=2*r1 所以r1有唯一解：r1=(L1-L2+L3)/2.0 r2=L1-r1 r3=L2-r2 ..... 依次检查r1到r2是否＜0   当n%2==0 假如n=4 r1+r2

>>阅读原文<<