leetcode 236. Lowest Common Ancestor of a Binary Tree 解题报告
原题连接 原题连接java 解题思路 第一遍代码超时了。思路（递归左子树，右子树，找到左右子树是否含有目标的TreeNode）这里有个坑，刚开始我是对比TreeNode.val是否相等判断是否含有，后来发现测试案例有不少相等的val，才知道应该判断此treenode是否相等。 修改后的代码以下（AC），思路是同样的实现比第一遍简洁多了，也是递归。若是当前根和其中任一匹配，直接返回当前根，必然是当前
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