SQL多个逗号分开的字段值 取对应的数据名称信息

字段值

 

函数实现：

ALTER function [dbo].[GetName](@strs NVARCHAR(500)) RETURNS NVARCHAR(4000) as
begin
 set @strs=','+@strs+','
 DECLARE @str1 NVARCHAR(4000) DECLARE @str2 NVARCHAR(4000) set @str2=''
 declare SyncOrderCursor cursor for 
 select b.Name from dbo.ShopStore as a inner join dbo.Shop as b  on a.StoreGid=b.Gid where @strs like  '%,'+cast(a.Gid as nvarchar(4000))+',%'
 open SyncOrderCursor fetch next from SyncOrderCursor into @str1
 while @@FETCH_STATUS=0
 begin
     set @str2=@str2+'|'+@str1
  fetch next from SyncOrderCursor into @str1
 end
 close SyncOrderCursor deallocate SyncOrderCursor return @str2
End

---另外一种实现方式 --select A.Gid,stuff(( -- select '|'+B.Name from Shop B -- where charindex(','+CAST(B.Gid as varchar(8000))+',',','+ CAST (B.Gid as varchar(8000))+',')>0 -- order by B.Gid -- for xml path('') -- ),1,1,'') as name  --from ShopStore A

调用函数实现：

 [dbo].GetName(Gids) AS ShopName

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