【题意】:开6条线程计算累加1 -> 10000000多线程
【思路】:生产者-消费者 经典模型ide
/** * 多线程计算累加数 */ public class Accumulate { public static void main(String[] args) { Storage storage = new Storage(); // 为多个计算器对象建立线程 Thread calThread1 = new Thread(new Calculate(1, storage), "Thread-1"); Thread calThread2 = new Thread(new Calculate(2, storage), "Thread-2"); Thread calThread3 = new Thread(new Calculate(3, storage), "Thread-3"); Thread calThread4 = new Thread(new Calculate(4, storage), "Thread-4"); Thread calThread5 = new Thread(new Calculate(5, storage), "Thread-5"); Thread calThread6 = new Thread(new Calculate(6, storage), "Thread-6"); calThread1.start(); calThread2.start(); calThread3.start(); calThread4.start(); calThread5.start(); calThread6.start(); // 打印最终结果 storage.printTotal(); } } /** * 计算器对象,负责计算start -> end */ class Calculate implements Runnable { private Storage storage; private long start; public Calculate(long start, Storage storage) { this.start = start; this.storage = storage; } @Override public void run() { long num = start; long sum = 0; while (num <= 10000000) { System.out.println(Thread.currentThread().getName() + " add num " + num); sum += num; num += 6; } // 线程计算完毕, 调用累加器进行累加 storage.push(sum); } } /** * 仓库对象,负责累加 */ class Storage { private long total = 0; private int count = 0; public synchronized void push(long sum) { total += sum; count++; notifyAll(); } public synchronized void printTotal() { while (count < 6) { try { System.out.println(Thread.currentThread().getName() + " is wait"); wait(); } catch (InterruptedException e) { e.printStackTrace(); } } System.out.println("storage result = " + total); } }